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Aleksandr-060686 [28]
3 years ago
12

Which function has lowest rate of change?

Mathematics
1 answer:
Delvig [45]3 years ago
8 0

Answer:

A: Algebraic Function

Step-by-step explanation:

Algebraic function is given as;

5x – 2y = 15

Since we are dealing with rate of change, let's make y the subject first and find dy/dx.

Thus;

2y = 5x - 15

y = (5x/2) - 15/2

dy/dx = 5/2

dy/dx = 2.5

The verbal function is given as;

Cost of 5 pencils is 15 dollars

Thus, rate of 1 pencil = 15/5 = 3 pencils per dollar

We can see that the lowest rate of change is 2.5 and it is the algebraic function.

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Write down the explicit solution for each of the following: a) x’=t–sin(t); x(0)=1
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Answer:

a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)

Step-by-step explanation:

Let's solve by separating variables:

x'=\frac{dx}{dt}

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\int {} \, dx=\int {(t-sint)} \, dt\\\\x=\frac{t^2}{2}+cost +k

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Finally:

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b) x’+2x=4; x(0)=5

dx=(4-2x)dt\\\\\frac{dx}{4-2x}=dt \\\\\int {\frac{dx}{4-2x}}= \int {dt}\\

Completing the integral:

-\frac{1}{2} \int{\frac{(-2)dx}{4-2x}}= \int {dt}

Solving the operator:

-\frac{1}{2}ln(4-2x)=t+k

Using algebra, it becomes explicit:

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c) x’’+4x=0; x(0)=0; x’(0)=1

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m^{2}e^{mt}+4(e^{mt})=0\\\\m^{2}+4=0\\\\m^{2}=-4\\\\m=2i

This becomes the solution <em>m=α±βi</em> where <em>α=0</em> and <em>β=2</em>

x=e^{\alpha t}[Asin\beta t+Bcos\beta t]\\\\x=e^{0}[Asin((2)t)+Bcos((2)t)]\\\\x=Asin((2)t)+Bcos((2)t)

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