All categories

2 years ago

Cana you pls help me

Mathematics

2 answers:

almond37 [142]2 years ago

7 0

Answer:

Yes I agree with the person above because pattern A is adding by 3.

sashaice [31]2 years ago

4 0

Answer:

Step-by-step explanation:

In pattern A, we see that each number is 3 more than the one before it. B is incorrect because the pattern is +9. C is incorrect because the numbers in Pattern A is 3x Less than the corresponding numbers in Pattern B. D is incorrect because the numbers in Pattern B are 3x more than the numbers in Pattern A.

Hope this helps!

You might be interested in

(ANSWER ASAP) Solve the inequality.

Aleksandr [31]

Answer:

-4≤ g

Step-by-step explanation:

subtract the 7 to move the numbers to one side

7 0

2 years ago

Read 2 more answers

Solve the two-step equation. 5.1 = –3x – 4.2 1. Add 4.2 to both sides. 2. Divide both sides by -3. The solution is x = _________

Serggg [28]

Answer:

5.1 = -3x - 4.2

-3x - 4.2 = 5.1

-3x = 5.1 + 4.2

-3x = 9.3

x = 9.3/-3

x = -3.1

6 0

3 years ago

Read 2 more answers

Find the surface area of a cone with radius 14.2 inches and slant height 24.1 inches.

ololo11 [35]

Answer:

1708.58658058

Step-by-step explanation:

Total surface area formula = (π×r²)+(π×r×s)

r = radius

s = slant height

So we substitute the values into the formula (π×r²)+(π×r×s)

(π×14.2²)+(π×14.2×24.1) = 1708.58658058

8 0

3 years ago

Which of the following is a direct proportion? A. y=7x B. y=x+7 C. y=7x−7 D. y=7

AveGali [126]

The answer is D) y=7

5 0

3 years ago

A sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

TEA [102]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ = $1,150

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $1,150

(b) The test statistic is 3.571.

(c) We conclude that the mean of all account balances is significantly different from $1,150.

Step-by-step explanation:

We are given that a sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

We have test the hypothesis to determine whether the mean of all account balances is significantly different from $1,150.

Let $\mu$ = mean of all account balances

(a)So, Null Hypothesis, $H_0$ : $\mu$ = $1,150 {means that the mean of all account balances is equal to $1,150}

Alternate Hypothesis, $H_A$ : $\mu$ $\neq$ $1,150 {means that the mean of all account balances is significantly different from $1,150}

The test statistics that will be used here is One-sample t test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average balance = $1,200

s = sample standard deviation = $126

n = sample of account balances = 81

(b) So, test statistics = $\frac{1,200-1,150}{\frac{126}{\sqrt{81} } }$ ~ $t_8_0$

= 3.571

The value of the sample test statistics is 3.571.

(c) Now, P-value of the test statistics is given by the following formula;

P-value = P( $t_8_0$ > 3.571) = Less than 0.05%

Because in the t table the highest critical value for t at 80 degree of freedom is given between 3.460 and 3.373 at 0.05% level.

Now, since P-value is less than the level of significance as 5% > 0.05%, so we sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean of all account balances is significantly different from $1,150.

8 0

3 years ago