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xeze [42]
3 years ago
15

Sarah had 25 candies. Sarah gave 25 of the candies to her sister. Of the amount left, she gave 2/3 to her friend. How many candi

es does Sarah have left for herself?
Mathematics
1 answer:
RoseWind [281]3 years ago
5 0

Answer:

She has 5 candles left.

Step-by-step explanation:

Total of candy Sarah has = 25candies

If Sarah gave 2/5 of the candies to her sister, the total amount she gave her sister will be 2/5 of 25

2/5 of 25 = 10

The remaining candy left will be 25-10 which is 15.

If she gave 2/3 of the amount left to her friend, the amount she gave her friend will be 2/3×15 = 10candies.

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Basically you just need to multiply the two fractions together to get the depth of the turtle. Therefore the turtle is 3/12 miles deep or 1/4 mile deep.
7 0
3 years ago
Please help me with this. Just have to write the equation. If you can solve, then you get brainliest guaranteed!
Temka [501]

x = player1

y = player 2

z = player 3

y = 2x  or 1/2 y =x

y = z-10  or z = y+10

x+y+z=70

substitute x= 1/2 y and z = y+10 into the above equation

1/2y + y + y+10 = 70

2.5 y + 10 = 70

subtract 10 from each side

2.5 y = 60

divide by 2.5 on each side

y = 60/2.5

y =24

x = 1/2 y

x = 1/2 *24 = 12

z = y+10 = 24+10 = 34

The three players scored 12, 24, 34


4 0
3 years ago
Read 2 more answers
Am i true<br> S six<br> C cruel<br> H hours<br> O of<br> O our<br> L Life
Licemer1 [7]

Answer:

yes school is amazing

4 0
2 years ago
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(ASAP PICTURE ADDED) What is the simplified form of the following expression?
bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)

WE need to simplify this equation.

Solve the parenthesis of each term.

=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation:=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)

Adding like terms we get:

=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\

(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)

So, option c is correct

5 0
3 years ago
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Braniliest ASAP<br><br><br> thanks!
Leokris [45]
The answer that you are looking for is d
3 0
3 years ago
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