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White raven [17]
3 years ago
8

Chase and Emily are buying stools for their patio. They are deciding between 3 heights (table height, bar height, and XL height)

and 3 colors (brown, white, and black). They each created a display to represent the sample space of randomly picking a height and a color.
Mathematics
1 answer:
vfiekz [6]3 years ago
8 0

Answer:

Neither

Step-by-step explanation:

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Natali5045456 [20]

x = 72

Step-by-step explanation:

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3 years ago
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A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
Delvig [45]

Answer:

Step-by-step explanation:

a) We would set up the hypothesis test.

For the null hypothesis,

p = 0.25

For the alternative hypothesis,

p ≠ 0.25

b) The test statistic to be used is the z test. The formula is

z = (P - p)/√pq/n

c) Considering the population proportion, probability of success, p = 0.25

q = probability of failure = 1 - p

q = 1 - 0.25 = 0.75

Considering the sample,

Sample proportion, P = x/n

Where

x = number of success = 141

n = number of samples = 600

P = 141/600 = 0.235

Therefore

z = (0.235 - 0.25)/√(0.25 × 0.75)/600 = - 0.85

d) Recall, population proportion, p = 0.25

The difference between sample proportion and population proportion is 0.25 - 0235. = 0.015

Since the curve is symmetrical and it is a two tailed test, the p for the left tail is 0.25 - 0.015 = 0.235

the p for the right tail is 0.25 + 0.015 = 0.265

These proportions are lower and higher than the null proportion. Thus, they are evidence in favour of the alternative hypothesis. We will look at the area in both tails. Since it is showing in one tail only, we would double the area

From the normal distribution table, the area below the test z score in the left tail 0.198

We would double this area to include the area in the right tail of z = 0.85. Thus

p = 0.198 × 2 = 0.396

e) Since alpha, 0.01 < than the p value, 0.396, then we would fail to reject the null hypothesis.

f) In a sample of 600 cars, we would observe a sample proportion of 0.015 or more away from 0.25 about 39.6% of the time by chance alone. Therefore, the sample result is not statistically significant because it could occur in 39.6% of the time by chance alone.

8 0
3 years ago
I need help getting the answer could you help me by chance to receive brainlest!?
Pani-rosa [81]
(Placeholder because it won’t let me ask more questions until I answer some)
5 0
3 years ago
In a random sample of 45 newborn babies, what is the probability that 40% or fewer of the sample are boys. (Use 3 decimal places
erastova [34]

Answer:

z= \frac{p- \mu_p}{\sigma_p}

And the z score for 0.4 is

z = \frac{0.4-0.4}{\sigma_p} = 0

And then the probability desired would be:

P(p

Step-by-step explanation:

The normal approximation for this case is satisfied since the value for p is near to 0.5 and the sample size is large enough, and we have:

np = 45*0.4= 18 >10

n(1-p) = 45*0.6= 27 >10

For this case we can assume that the population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Where:

\mu_{p}= \hat p = 0.4

\sigma_p = \sqrt{\frac{p(1-p)}(n} =\sqrt{\frac{0.4(1-0.4)}(45}= 0.0703

And we want to find this probability:

P(p

And we can use the z score formula given by:

z= \frac{p- \mu_p}{\sigma_p}

And the z score for 0.4 is

z = \frac{0.4-0.4}{\sigma_p} = 0

And then the probability desired would be:

P(p

7 0
3 years ago
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If I have 18 credits and need 23 to graduate high school how many semesters do I need to take? one or two???
sammy [17]

Depending on what classes, most likely one.

7 0
3 years ago
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