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Leona [35]
3 years ago
9

If log 2^x = log 3, then which is the value of x?

Mathematics
1 answer:
natulia [17]3 years ago
8 0

There's a property of logs I want you to remember, that is:

log(a)ᵇ = b*log(a)

We'll be using this property to solve the question

<u>Finding x:</u>

log(2)ˣ = log(3)

x*log(2) = log(3)                                     [using the property mentioned above]

x = log(3) / log(2)                                 [dividing both sides by log(2)]

Hence, the correct answer is option E.

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Help please!!!!!...........................
Finger [1]

Answer:

See solution :)

Step-by-step explanation:

Let us first analyse our information given. The question tells us that each person, (i.e. Jamie and Stella) should pay $600 upfront. Thus, our first constraint (lets call it T) is that any total amount of money must be equal or more than $600, which in maths notation reads:

T\geq 600

<em>where \geq means More or Equal to.  </em>

We also know that Jamie washes care for $25 dollars and if represented in math notation, we can say that for every car (denoted by) x, Jamie makes $25, thus for Jamie we have:

J: 25x

Similarly we know that Stella makes pecan pies and for each pie she sells she makes $15, so we can say that<em> for every pecan pie (denoted by) y, Stella makes $15, thus for Stella we have:</em>

S: 15y

However, we also know that Stella does not have enough supplies for more than 40 pies, which puts a constraint on the amount of money she can make by selling pecan pies. <em>Therefore we can now say that</em>

15y is true, for y\leq 40

<em>where y\leq 40 is the constraint on Stellas possible profits and \leq means Less or Equal to. </em>

<u>Now lets start answering the questions: </u>

Part 1: Write a constraint (an inequality) to represent how much money Jamie needs for his trip.

Answer:  25x

*provided that 25x\geq 600 (in order to make the neccesary profit)

Part 2: Write a constraint (an inequality) to represent how much money Stella needs for her trip.

Answer:  15y\geq600 and  y\leq40

Part 3: Write a constraint (an inequality) to represent the relationship between Jamie's earnings and Stella's earnings.

Answer: Since Stella can not make more than 40 pies, the solution intersection between Jamie and Stella is y\geq 40 (Jamie) ∩ y\leq40 (Stella), thus y=40.

Part 4: Can Stella afford to sign up for the trip with the money she earns? Explain your answer and show any work that might support your answer.

Answer: We know that Stella's pie making is denoted by 15y, and the total amount needed for the trip upfront is denoted by T\geq 600 therefore to find if Stella can afford to sign up, we need to find the amount of pies Stella needs to produce, in order to make a profit of at least $600. Thus we write:

15y\geq 600\\y\geq \frac{600}{15}\\ y\geq 40

Since the number of pies Stella needs to make, to gain a profit of $600 is 40 pies, and we know that Stella can make a maximum of 40 pies with the supplies she already has, we can conclude that Stella can make the necessary money to make her trip to Washington!

5 0
3 years ago
The teams ratio of games won to games played was 5 to 6 If. The team played 36 games, how many games did the team fail to win
Scrat [10]

Answer:The team failed to win 6 games.

Step-by-step explanation: 5/6 has to be equal to something over 36. Since you multiplied the denominator by 6 you have to multiply the numerator by 6 and 5*6 equals 30. If out of 36 games they won 30. Then to find how many games they lost all that you have to do is subtract 36 and 30 to get 6.

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3 years ago
Answer correctly , will mark brainliest answer !!!!
Darya [45]

Answer:

width : x+4

Step-by-step explanation:

(x+9)(x+4) = x^2+4x+9x+36

x^2+13x+36

think of numbers that multiply together to get 36

and of those number, what numbers add up to 13

9 times 4 equals 36

9 plus 4 equals 13

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Fraction has a fraction in the<br> numerator, denominator, or both
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A fraction is numerator over denominator, most of the time whole numbers
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Can someone help me translate this into simpler and easier words? Create a line of best fit. Position your ruler on the graph to
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