Total volume of water=12*10*11
Let final height of water be h
Total volume of water=h*(12*10+7*10+6*5)
1/3 x (3^-2 x 3^5)
1/3 x (1/3^2 x 243)
1/3 x (1/9 x 243)
1/3 x 27
9
So it's best in this case to separate both shapes so you have a rectangle and a triangle so to solve the area of a rectangle you do
The following ( picture )
So I hope this helps
Step-by-step explanation:
A ball is launched straight up in the air from a height of 6 feet. The velocity as a function of time t is given by :
f(t) = -32 t+285
Height of the ball is :

C is constant. Here the ball is launched from a height of 6 feet. So,

At t = 2 s, 
At t = 9 s, 
Between 2 s and 9 s, the ball's height changed is : 1275 - 512 = 763 m.