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balu736 [363]
2 years ago
11

How do you solve for (w-2)²-63=0 where w is a real number

Mathematics
1 answer:
Murrr4er [49]2 years ago
4 0
(w-2)^2 = 63

FOIL left hand side:
(w-2)^2 = w^2 - 4w + 4

So,
w^2 - 4w + 4 = 63
w^2 - 4w - 59 = 0

Then use quadratic equation to get values of w = 2 + 3*root(7) and w = 2 - 3*root(7).
±
3
√
7
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HELP !! a sandwich shop purchases a used pizza oven for $875. after 5 years, the oven will have to be discarded and replaced. wr
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<h3>Answer: V = -175t + 875</h3>

==================================================

Explanation:

I'll use y in place of V for now. Also, I'll use x in place of t.

x = number of years

y = value of the oven

Initially, the oven's value is $875, so x = 0 and y = 875 pair up together. The point (0,875) is on the line.

The point (5, 0) is also on the line to indicate that x = 5 years later is when the value of the oven is y = 0 dollars.

We need to find the equation of the line through (0,875) and (5,0)

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m = (0-875)/(5-0)

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The negative slope means the oven is losing 175 dollars in value each year.

The y intercept is b = 875 as this is the initial value of the oven

Put together, y = mx+b turns into y = -175x+875

If we plugged x = 0 into this equation, we'd get y = 875

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2 years ago
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