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tensa zangetsu [6.8K]
3 years ago
8

-3 1/2 x 5 5/6. Plz help me what's the answer plz

Mathematics
1 answer:
Kitty [74]3 years ago
4 0
Exact Form: -245/12 , Decimal Form: -20.4166666, or Mixed Number Form: -20 5/12
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Which statement about the following equation is true?
spayn [35]

The given expression is

3x^2 -8x +5 = 5x^2

We have to find the discriminant first . And for that, first we need to move whole terms of the left side to right side, that is

5x^2 -3x^2 +8x -5=0

2x^2+ 8x -5 =0

The formula of discriminant is

D =b^2 -4ac

Substituting the values of a,b and c, we will get

D = 8^2 -4(2)(-5)=64+40 = 104

And since the discriminant is greater than 0, or it is positive so we have two real roots.

Therefore the correct option is B .

7 0
3 years ago
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Please answer correctly !!!!!! Will mark brainliest answer !!!!!!!!!!!!!!
AlekseyPX

Answer:

(up) by 6

left by 7

Step-by-step explanation:

7 0
3 years ago
Find the perimeter of the shape shown below.
sukhopar [10]

perimeter = turn of the figure

P = 6 + 3 + 4 + 4 + 3 + 6 + 3 + 4 + 3 = 36

the triangle has 2 équal sides => isosceles

and 1 angle is 60° so the triangle is equilateral

 

7 0
2 years ago
A total of 259 tickets were sold to a benefit concert for a total of $5,312. Two types of tickets were sold: adult tickets were
jeyben [28]

Answer:

113

Step-by-step explanation:

Let the number of adult tickets sold =a

Let the number of student tickets sold =s

A total of 259 tickets were sold, therefore:

a+s=259

Adult tickets were sold for $24 each and student tickets were sold for $16 each.

Total Revenue = $5,312

Therefore:

24a+16s=5,312

We solve the two derived equations simultaneously.

From the first equation

a=259-s

Substitute a=259-s into 24a+16s=5,312

24(259-s)+16s=5,312

6216-24s+16s=5,312

-8s=5,312-6216

-8s=-904

Divide both sides by -8

s=113

Therefore, 113 student tickets were sold.

4 0
3 years ago
State whether the triangles could be proven congruent, if possible, by SSS or SAS.
Helen [10]

Answer:

1. SSS

2. SAS

3. SAS

4. SSS

5. SAS

6. SAS

Step-by-step explanation:

1) Side FY ≅ Side CW  Given

Side FP ≅ Side CM     Given

Side YP ≅ Side MW    Given

∴ΔMCW ≅ ΔFPY by the Side-Side-Side (SSS) rule of congruency

2) ∠CBD ≅ ∠BCA given that both are alternate interior angles

Side EB ≅ Side EC and Side DB ≅ Side CA Given

ΔBED ≅ ΔAEC by Side-Angle-Side (SAS) rule of congruency

3. ∠SVU ≅ ∠SVT   Given

Side SV ≅ Side SV  by reflexive property

Side VT ≅ Side VU   Given

∴ ΔVSU ≅ ΔVST by Side-Angle-Side (SAS) rule of congruency

4. Side MN ≅ Side QP  Given

Side MQ ≅ Side NP     Given

Side NQ ≅ Side NQ    by reflexive property

∴ΔQNM ≅ ΔQNP by the Side-Side-Side (SSS) rule of congruency

5. Indirect proof

Side GL ≅ Side HL  Given

Side GJ ≅ Side HK     Given

∠JLG ≅ ∠HLK    vertically opposite angles

By sine rule

GJ/sin(∠JLG) = GL/n(∠GJL)

Similarly

HK/sin(∠HLK) = HL/n(∠HKL)

∴ ∠GJL ≅ ∠HKL

∴ ∠LGJ ≅ ∠LHK third angle of two triangles given the other two angles are congruent

∴ΔQNM ≅ ΔQNP by the Side-Angle-Side (SAS) rule of congruency

6. ∠XZY ≅ ∠XZW   Supplementary ∠s with ∠XZY = 90°

Side XZ ≅ Side XZ  by reflexive property

Side ZW ≅ Side ZY   Given

∴ ΔXYZ ≅ ΔXWZ by Side-Angle-Side (SAS) rule of congruency.

3 0
2 years ago
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