I think the answer is C but I could be wrong
I believe malware fraud, c.
Answer:
The corrected question is:
Write an SQL statement to display the WarehouseID, the sum of QuantityOnOrder and sum of QuantityOnHand, grouped by WarehouseID and QuantityOnOrder. Name the sum of QuantityOnOrder as TotalItemsOnOrder and the sum of QuantityOnHand as TotalItemsOnHand. Use only the INVENTORY table in your SQL statement.
Answer to this corrected question:
SELECT WarehouseID,
SUM(QuantityOnOrder) AS TotalItemsOnOrder,
SUM(QuantityOnHand) AS TotalItemsOnHand
FROM INVENTORY
GROUP BY WarehouseID, QuantityOnOrder;
According to the given question:
SELECT WarehouseID,
SUM(QuantityOnOrder) + SUM(QuantityOnHand) AS TotalItemsOnHand
FROM INVENTORY
GROUP BY WarehouseID, QuantityOnOrder;
Explanation:
- In the SQL statement SELECT statement is used to select the data from the table. Here the SELECT statement is used to select WarehouseID, Sum of the columns QuantityOnOrder and QuantityOnHand from INVENTORY table.
- The sum of QuantityOnOrder and QuantityOnHand columns are given the name of TotalItemsonHand (In case of the corrected question the sum of column QuantityOnOrder is named as TotalItemsOnOrder and the column QuantityOnHand is named as TotalItemsOnHand
) using Alias AS. Alias is the temporary name given to the columns or table to make them more readable.
- GROUP BY statement is used to arrange or "group" same data and is often use with aggregate functions like SUM function here. So the grouping here is done based on two columns WarehouseID and QuantityOnOrder.
- SUM function in this SQL statement is an aggregate function to calculate the sum of all value in the columns QuantityOnOrder and QuantityOnHand.
Answer:
Altitude of the town(h1) = 1,196.8 m
Explanation:
Given:
Height of barometer(h) = 65 cm Hg = 0.65
Standard atmospheric pressure = 76 cm Hg = 0.76
Density of mercury(Pm) = 13,600 kg/m³
Density of air (Pa) = 1.25 kg/m³
Find:
Altitude of the town(h1)
Computation:
Pressure due column = Δp mercury column
(Pa)(h1) = (Pm)(h)
(1.25)(h1) = (13,600)(0.76-0.65)
(1.25)(h1) = 1,496
Altitude of the town(h1) = 1,196.8 m
