1. - Since a cube is all the same lengths on all sides you would want to find the area of one of the sides. You would do this by multiplying 3.8 by 3.8.
3.8*3.8=14.44
Since you have six faces on a cube you want to multiply this by 6.
14.44*6=86.64
So your answer for 1. is 86.64 in^2 of glass
3. Same thing as number one. Find the face of one side:
1 1/3*1 1/3 is about 1.7777
Multiply this by the six faces.
1.7777*6 is about 10.66666
So your answer for 3. is about 10.666 (repeating) in^2
4. For this one, you want to follow the surface area formula for a cylinder. Which is - A=2πrh+2πr^2
When you put all your numbers in it would look like this:
2*3.14*2*22+2*3.14*2^2
Once you do that equation you will get 301.44
So that should be your answer 301.44 cm^2
Hope this helps!
The answer would be A. If 4x + 6 is the number of boats made in 1 day, then multiplying that by 12 would give us the number of boats made in 12 days so the equation would look like this:
12(4x + 6)
(1-cos^2(x)) csc^2(x)=1
one of the trigonometry rules is sin^2(x) + cos^2(x) = 1 if you rearrange this you realize that sin^2= 1-cos^2(x)
we also know that csc^2(x)= 1/sin^2(x) so now you can rewrite your equation as:
sin^2(x) x 1/sin^2(x) = 1
sin^2(x)/sin^2(x) =1
the LHS (left hand side) can cancel down to 1 because the numerator and denominator are the same
so then 1=1 Therefore LHS=RHS
Hope this helps
Answer:
Step-by-step explanation:
26% is (26-20)/(50-20) = 6/30 = 1/5 of the way between 20% and 50%. That means 1/5 of the solution is 50% acid.
50% acid: 1/5 · 100 mL = 20 mL
20% acid: 100 mL -20 mL = 80 mL
Delbert must mix 80 mL of 20% acid and 20 mL of 50% acid.
_____
Maybe you'd like to see an equation. Let x represent the amount of 50% acid required. Then 100-x is the amount of 20% acid needed. The amount of acid in the mix is ...
0.50(x) +0.20(100 -x) = 0.26(100)
(0.50 -0.20)x = (0.26 -0.20)100 . . . . subtract 0.20(100)
x = (0.26 -0.20)/(0.50 -0.20)×100 = 20
This last expression should look a lot like the one we started with in this answer. It shows you how you can almost write down the answer to mixture problems without a lot of work.
Answer:
What exactly is your question?
Step-by-step explanation:
