Ask question

Ask question

All categories

3 years ago

11

You want to draw an enlargement of a design that is printed on a card that is 5 in. by 6 in. You will be drawing this design on

an piece of paper that is 8.5 in. by 11 in. What are the dimensions of the largest complete enlargement you can make?

1 answer:

jonny [76]3 years ago

6 0

Answer:

The dimensions of the largest enlargement are

$8\frac{1}{2}\ in\\10\frac{1}{5}\ in$

Step-by-step explanation:

we know that

If two figures are similar, then the scale factor is the ratio of its corresponding sides

step 1

Divide 8 1/2 by 5

$8\frac{1}{2}=\frac{8*2+1}{2}=\frac{17}{2}\ in$

so

$\frac{17}{2}/5=1.7$

step 2

Divide 11 by 6

so

$\frac{11}{6}=1.83$

step 3

Find the largest complete enlargement

The scale factor is the smaller of the two previous values

so

The scale factor is 1.7

The dimensions are

$5(1.7)=8.5=8\frac{1}{2}\ in$

$6(1.7)=10.2=10\frac{1}{5} \ in$

You might be interested in

3 If the function f(x)=2x-3 and g(x)=x+1 then which of the following is a true statement? 2 (1) f(0)>g(0) (3) f (8)=g(8) (2)

lapo4ka [179]

Answer:2(1)

Step-by-step explanation:

3 0

2 years ago

Edward was running errands on his bike first to be like from his house to the post office to pick up a package the post office i

Karo-lina-s [1.5K]

Answer:

Edward drove altogether of 16.1 miles.

Step-by-step explanation:

Given:

Edward was Running around on his bike.

Distance from home to post office = $4 \frac{4}{5} \ miles$

$4 \frac{4}{5} \ miles$ can be Rewritten as $4.8 \ miles$

Distance from home to post office = $4.8 \ miles$

Now Given:

Distance from Post office to market = 3.25 miles.

Now we will calculate Distance from Home to market.

Distance from Home to market can be calculated by adding Distance from home to post office and Distance from Post office to market.

Framing in equation form we get;

Distance from Home to market = $4.8+3.25 = 8.05\ miles$

Also Given:

his mother picked him up at the market and drove him home.

We need to find the total miles Edward drive altogether.

total miles Edward drive altogether will be equal to Sum of Distance from Home to market and Distance from market to home.

framing in equation form we get;

Total Distance Edward drove = $8.05+8.05 = 16.1\ miles$

Hence Edward drove altogether of 16.1 miles.

5 0

2 years ago

tickets for a lower level seats sell for $35 each and tickets for an upper level seats sell for $25 each. the theater sells 350

Liono4ka [1.6K]

The work and answer is shown in the image below. Just set the variables and solve.

5 0

2 years ago

A fair coin is to be tossed 20 times. Find the probability that 10 of the tosses will fall heads and 10 will fall tails, (a) usi

lbvjy [14]

Using the distributions, it is found that there is a:

a) 0.1762 = 17.62% probability that 10 of the tosses will fall heads and 10 will fall tails.

b) 0% probability that 10 of the tosses will fall heads and 10 will fall tails.

c) 0.1742 = 17.42% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item a:

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

20 tosses, hence $n = 20$ .
Fair coin, hence $p = 0.5$ .

The probability is <u>P(X = 10)</u>, thus:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{20,10}.(0.5)^{10}.(0.5)^{10} = 0.1762$

0.1762 = 17.62% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item b:

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
The binomial distribution is the probability of <u>x successes on n trials, with p probability</u> of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

The probability of an exact value is 0, hence 0% probability that 10 of the tosses will fall heads and 10 will fall tails.

Item c:

For the approximation, the mean and the standard deviation are:

$\mu = np = 20(0.5) = 10$

$\sigma = \sqrt{np(1 - p)} = \sqrt{20(0.5)(0.5)} = \sqrt{5}$

Using continuity correction, this probability is $P(10 - 0.5 \leq X \leq 10 + 0.5) = P(9.5 \leq X \leq 10.5)$ , which is the <u>p-value of Z when X = 10.5 subtracted by the p-value of Z when X = 9.5.</u>

X = 10.5:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{10.5 - 10}{\sqrt{5}}$

$Z = 0.22$

$Z = 0.22$ has a p-value of 0.5871.

X = 9.5:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{9.5 - 10}{\sqrt{5}}$

$Z = -0.22$

$Z = -0.22$ has a p-value of 0.4129.

0.5871 - 0.4129 = 0.1742.

0.1742 = 17.42% probability that 10 of the tosses will fall heads and 10 will fall tails.

A similar problem is given at brainly.com/question/24261244

6 0

2 years ago

A restaurant offers a "Create Your Own Pizza" menu option. There are 33 types of meat, 66 types of vegetables, and 33 kinds of c

OleMash [197]

Answer:

54

Step-by-step explanation:

You have to do the number of options in each category by itsself

5 0

2 years ago