Answer:
i dont know
i need the same help
Step-by-step explanation:
Given:
Street C is perpendicular to Street A and passes through (4, -6).
The equation of street A is:

To find:
The equation of street C.
Solution:
The equation of street A is:

On comparing this equation with slope intercept form
, we get

Slope of this line is -2.
We know that, the product of slopes of two perpendicular lines is always -1.




The slope of street C is
and it passes through the point (4,-6). So, the equation of street C is



Therefore, the point slope form of the street C's equation is
.
Answer:
-5x - 16y - 24z
Step-by-step explanation:
5x - 2y - 6z - 10x - 14y - 18z
5x - 10x - 2y - 14y - 6z - 18z
-5x - 16y - 24z
One, because 1/1=1 right? No other number retains this property, except maybe zero but is 0/0 even possible?
The slope is 0 and the equation of the line is y= -2.