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miss Akunina [59]
3 years ago
15

Net pay is the difference between a worker’s gross income and his or her deductions. A person’s gross income for the year was $6

5,000 and their total deductions were $12,860. What was their net pay for the year? Use the formula P = I - d, where P is the net pay, I is the gross income and d is the deductions. a. $53,140 is the net pay b. $77,860 is the net pay c. $72,860 is the net pay d. $52,140 is the net pay
Mathematics
1 answer:
Tanzania [10]3 years ago
7 0
We are given that I = $65,000 and d = $12,860. Using the formula, we get:
P = 65000-12860 = 52140

So, the person's net pay is $52,140, and the answer is D.
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You always need some time to get up after the alarm has rung. You get up from 10 to 20 minutes later, with any time in that inte
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Answer:

a) P(x<5)=0.

b) E(X)=15.

c) P(8<x<13)=0.3.

d) P=0.216.

e) P=1.

Step-by-step explanation:

We have the function:

f(x)=\left \{ {{\frac{1}{10},\, \, \, 10\leq x\leq 20 } \atop {0, \, \, \, \, \, \,  otherwise }} \right.

a)  We calculate  the probability that you need less than 5 minutes to get up:

P(x

Therefore, the probability is P(x<5)=0.

b) It takes us between 10 and 20 minutes to get up. The expected value is to get up in 15 minutes.

E(X)=15.

c) We calculate  the probability that you will need between 8 and 13 minutes:

P(8\leq x\leq 13)=P(10\leqx\leq 13)\\\\P(8\leq x\leq 13)=\int_{10}^{13} f(x)\, dx\\\\P(8\leq x\leq 13)=\int_{10}^{13} \frac{1}{10} \, dx\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot [x]_{10}^{13}\\\\P(8\leq x\leq 13)=\frac{1}{10} \cdot (13-10)\\\\P(8\leq x\leq 13)=\frac{3}{10}\\\\P(8\leq x\leq 13)=0.3

Therefore, the probability is P(8<x<13)=0.3.

d)  We calculate the probability that you will be late to each of the 9:30am classes next week:

P(x>14)=\int_{14}^{20} f(x)\, dx\\\\P(x>14)=\int_{14}^{20} \frac{1}{10} \, dx\\\\P(x>14)=\frac{1}{10} [x]_{14}^{20}\\\\P(x>14)=\frac{6}{10}\\\\P(x>14)=0.6

You have 9:30am classes three times a week.  So, we get:

P=0.6^3=0.216

Therefore, the probability is P=0.216.

e)  We calculate the probability that you are late to at least one 9am class next week:

P(x>9.5)=\int_{10}^{20} f(x)\, dx\\\\P(x>9.5)=\int_{10}^{20} \frac{1}{10} \, dx\\\\P(x>9.5)=\frac{1}{10} [x]_{10}^{20}\\\\P(x>9.5)=1

Therefore, the probability is P=1.

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strojnjashka [21]
The question that is asked is pretty straight forward. Only thing that needs to be found is the number of 30 in the number 600. By dividing 600 by 30 we can arrive at the desired result.
Number of 30 in 600 = 600/30
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Number of 10 in 1000 = 1000/10
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