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Citrus2011 [14]
3 years ago
6

Please help!! How do I solve for x?

Mathematics
1 answer:
Mariana [72]3 years ago
5 0

The line in the middle is half the length of the line on the outside. Multiply the middle line by 2 and set it equal to the outside line.

2(x-3) = x + 6

Simplify:

2x -6 p x + 6

Add 6 to both sides

2x = x + 12

Subtract x from both sides:

X = 12

The answer is B) 12

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Multiply 8x(3/4y+4) using distributive property
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You multiply 8x by each number and get

24/4xy+32   You can simplify the 24/4 to get six. so your answer is

6xy+32

4 0
3 years ago
Y=? cm<br> A15<br> B.10<br> C.3<br> D.5
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3 0
3 years ago
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Land in downtown Columbia is valued at $10 a square foot. What is the value of a triangular lot with sides of lengths 119, 147,
stiks02 [169]

Answer:

$87,461

Step-by-step explanation:

Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft

where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.

S = (119 + 147 + 190) / 2 = 456/ 2 = 228

Using Heron's formula which gives the area in terms of the three sides of the triangle

= √s(s – a)(s – b)(s – c)

Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)

=> √228 (109)(81)(38)

= √228(335502)

=√76494456

= 8746.1109071 * $10

= 87461.109071

≈$87,461

Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.

6 0
3 years ago
Jesse takes his dog and cat for their annual vet visit.Jesse's dog weighs 23 pounds.The vet tells him his cat's weight is 5/8 as
Kobotan [32]
If I’m not mistaken the cats weight is 14.4
5 0
3 years ago
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agasfer [191]

Ans is -48.

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3 years ago
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