What is the area of a sector with a central angle of 4π5 radians and a radius of 11 cm?
2 answers:
Answer
Area of sector (A) is given by:
where,
r is the radius and is the angle in degree.
As per the statement:
A central angle of radians and a radius of 11 cm.
⇒r = 11 cm
Use conversion:
1 radian =
then;
radians =
⇒ degree
Substitute these given values and use 3.14 for π we have;
square cm.
Therefore, the area of a sector is, 151.976 square cm
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You just need to use your test-taking skill to eliminate the wrong answers here.
There is no such thing as a "Congruent Angles Postulate," so the last two choices can be eliminated.
The AA Similarity Postulate refers to triangles, not angles, so the second choice can be eliminated.
That only leaves the (correct) first choice.
Answer:
It is continuous since
Step-by-step explanation:
We are given that the function is defined as follows and
and we want to check the continuity in the interval [-4,5]. Note that this a piecewise function whose only critical point (that might be a candidate of a discontinuity) x=0 since at this point is where the function "changes" of definition. Note that 9-x and 9+12x are polynomials that are continous over all
. So F is continous in the intervals [-4,0) and (0,5]. To check if f(x) is continuous at 0, we must check that
(this is the definition of continuity at x=0)
Note that if x=0, then f(x) = 9-x. So, f(0)=9. On the same time, note that
. This result is because the function 9-x is continous at x=0, so the left-hand limit is equal to the value of the function at 0.
Note that when x>0, we have that f(x) = 9+12x. In this case, we have that
. As before, this result is because the function 9+12x is continous at x=0, so the right-hand limit is equal to the value of the function at 0.
Thus, , so by definition, f is continuous at x=0, hence continuous over the interval [-4,5].
147×100=14700
168×x=168x
14700÷168=87.5
100-87.5=12.5
Your answer is 12.5 percent of it were earned during the playoffs. Hope I was helpful.