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4 years ago

13

Maritza is buying wheels for her skateboard shop. She ordered a total of 92 wheels. If wheels come in packages of 4, how many pa

ckages will she receive ?

2 answers:

iogann1982 [59]4 years ago

5 0

92÷4 = 23

23 pakages of 4 wheels

poizon [28]4 years ago

4 0

92/4=23

...........................

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Mr. Harrow has eight boys and six girls in his Honors Precalculus class. If he randomly chooses two students, one at a time, wha

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What are the values for x and y?

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Answer:

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3 years ago

Match each spherical volume to the largest cross sectional area of that sphere

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Answer:

Part 1) $324\pi\ units^{2}$ ------> $7,776\pi\ units^{3}$

Part 2) $36\pi\ units^{2}$ ------> $288\pi\ units^{3}$

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Part 4) $144\pi\ units^{2}$ ------> $2,304\pi\ units^{3}$

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

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$r^{2}=324$

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The volume of the sphere is

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$V=\frac{4}{3}\pi (18)^{3}$

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Part 2) we have

$A=36\pi\ units^{2}$

The area of the circle is equal to

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so

$36\pi=\pi r^{2}$

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$r^{2}=36$

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$V=\frac{4}{3}\pi r^{3}$

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$V=\frac{4}{3}\pi (6)^{3}$

$V=288\pi\ units^{3}$

Part 3) we have

$A=81\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$81\pi=\pi r^{2}$

Solve for r

$r^{2}=81$

$r=9\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=9\ units$

substitute

$V=\frac{4}{3}\pi (9)^{3}$

$V=972\pi\ units^{3}$

Part 4) we have

$A=144\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

so

$144\pi=\pi r^{2}$

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$r^{2}=144$

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The volume of the sphere is

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For $r=12\ units$

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Read 2 more answers

Write 3 21/25 as a decimal

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The answer should be 3.84

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4 years ago

Kruka [31]

Answer: x = -3/4 can not be a rational zero of the polynomial.

Step-by-step explanation:

We have the polynomial:

6x^5 + ax^3 -bx -12 = 0.

The theorem says that:

If P(x) is a polynomial with integer coefficients, and p/q is a zero of P(x) then p is a factor of the constant term (in this case the constant term is -12) and q is a factor of the leading coefficient (in this case the leading coefficient is 6.).

The factors of -12 (different than itself) are (independent of the sign).

1, 2, 3, 4 and 6.

So p can be: 1, -1, 2, -2, 3, -3, 4, -4, 6, -6.

The factors of 6 are:

1, 2 and 3, so q can be 1, -1, 2, -2, 3, -3.

Then the option that can not be a zero of the polynomial is

x = -3/4

because the number in the denominator must be a factor of the leading coefficient, and 4 is not a factor of six.

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4 years ago