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lutik1710 [3]
3 years ago
7

Do you prefer Thai food or chinese food. is the question baised

Mathematics
2 answers:
Aneli [31]3 years ago
8 0

Answer:

None.....|:<

Step-by-step explanation:

Ksenya-84 [330]3 years ago
4 0
No, this would not be a biased question unless the people asked were all Thai people or all Chinese people. Then the information would be skewed because naturally, Chinese people would favor Chinese food and same for Thai. 
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In the adjoining figure O is the centre of the circle the tangent to the circle of radius 6 cm from the exterior point P of the
slamgirl [31]

Answer:

Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.

Let Q be the point onthe circle  in which, tangent make 90° with radius at Q.

PQ = 8 and OQ = 6

we get a right angled triangle  PQO right angled at Q.

so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==

therefore OP =10cm

we need nearest point from P, which is PA

PA = OP - OA= 10 -6=4cm

7 0
3 years ago
Help!!
Morgarella [4.7K]

Answer: median

Step-by-step explanation:

8 0
3 years ago
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ra1l [238]

Answer:

1) 4 members have both pencil's and eraser's

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5 0
3 years ago
I dont understand this at all. I really need help! ​
Westkost [7]

Hello!

\large\boxed{x^{4}}

Recall that:

\sqrt[z]{x^{y} } is equal to x^{\frac{y}{z} }.  Therefore:

\sqrt[3]{x^{2} } = x^{\frac{2}{3} }

There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:

(x^{\frac{2}{3} })^{6}  = x^{\frac{2}{3}* 6 }  = x^{\frac{12}{3} } = x^{4}

3 0
3 years ago
The centers for disease control and prevention reported that 25% of baby boys 6-8 months old in the united states weigh more tha
melisa1 [442]

Answer:

0.1971 ( approx )

Step-by-step explanation:

Let X represents the event of weighing more than 20 pounds,

Since, the binomial distribution formula is,

P(x)=^nC_r p^r q^{n-r}

Where, ^nC_r=\frac{n!}{r!(n-r)!}

Given,

The probability of weighing more than 20 pounds, p = 25% = 0.25,

⇒ The probability of not weighing more than 20 pounds, q = 1-p = 0.75

Total number of samples, n = 16,

Hence, the probability that fewer than 3 weigh more than 20 pounds,

P(X

=^{16}C_0 (0.25)^0 (0.75)^{16-0}+^{16}C_1 (0.25)^1 (0.75)^{16-1}+^{16}C_2 (0.25)^2 (0.75)^{16-2}

=(0.75)^{16}+16(0.25)(0.75)^{15}+120(0.25)^2(0.75)^{14}

=0.1971110499

\approx 0.1971

3 0
3 years ago
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