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gayaneshka [121]
2 years ago
14

Raymond takes a 28-inch by 21-inch rectangle of plywood and uses a table saw to cut from one corner of the piece of plywood to t

he diagonally opposite corner. Now Raymond has two equally sized triangles of plywood. What is the perimeter of each triangle?
Mathematics
1 answer:
Katena32 [7]2 years ago
3 0

Step-by-step explanation:

just to fit characters ...........

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Which is true about the area of the parallelogram?
Colt1911 [192]

Answer:

area is 2 dimensional lika a carpet and a area rug. a parallelogram 4 sided-shape formed by 2 pairs of parrel lines. opposite sides are equal in lenght and opposite are equal in measure. to find the area of a parallegram, multiply the by the base by the height

Explanation:

Pls make me as brainliest and add as my friend i will check it.

3 0
3 years ago
Read 2 more answers
The question is given in the picture.
lorasvet [3.4K]
This is a really interesting question! One thing that we can notice right off the bat is that each of the circles has the same amount of area swept out of it - namely, the amount swept out by one of the interior angles of the hexagon. Let’s call that interior angle θ. We know that the amount of area swept out in the circle is proportional to the angle swept out - mathematically

θ/360 = a/A

Where “a” is the area swept out by θ, and A is the area of the whole circle, which, given a radius of r, is πr^2. Substituting this in, we have

θ/360 = a/(πr^2)

Solving for “a”:

a = π(r^2)θ/360

So, we have the formula for the area of one of those sectors; all we need to do now is find θ and multiply our result by 6, since we have 6 circles. We can preempt this but just multiplying both sides of the formula by 6:

6a = 6π(r^2)θ/360

Which simplifies to

6a = π(r^2)θ/60

Now, how do we find θ? Let’s look first at the exterior angles of a hexagon. Imagine if you were taking a walk around a hexagon. At each corner, you turn some angle and keep walking. You make 6 turns in all, and in the end, you find yourself right back at the same place you started; you turned 360 degrees in total. On a regular hexagon, you’d turn by the same angle at each corner, which means that each of the six turns is 360/6 = 60 degrees. Since each interior and exterior angle pair up to make 180 degrees (a straight line), we can simply subtract that exterior angle from 180 to find θ, obtaining an angle of 180 - 60 = 120 degrees.

Finally, we substitute θ into our earlier formula to find that

6a = π(r^2)120/60

Or

6a = 2πr^2

So, the area of all six sectors is 2πr^2, or the area of two circles with radii r.
5 0
2 years ago
A circle of centre M has a radius of 11CM . if CA=16.3cm ,what is AB ? give your answer to the nearest tenth!​
zhenek [66]

Answer:

16.4

Step-by-step explanation:

If it is asking for the tenth it will be the 1st one after the point and you round it to the next one.

6 0
2 years ago
Sarah completed about 85% of her school homework. Her friend Emily completed x percent homework more than Sarah. Which expressio
Ilia_Sergeevich [38]

Answer:

Step-by-step explanation:

85-x=100

85 represents sarah's hw

x represent Emily's hw

100 represents total completion

8 0
3 years ago
Read 2 more answers
20 points! Will mark the brainliest!
andrew-mc [135]
\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }

-----------------------------------------------------------------------------------
Write the divide fraction horizontally:
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}

-----------------------------------------------------------------------------------
Factorise the numerators and denominators when possible:
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}

-----------------------------------------------------------------------------------
Convert the divide fraction to multiplication fraction
-----------------------------------------------------------------------------------

= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}

-----------------------------------------------------------------------------------
Cancel the factors
-----------------------------------------------------------------------------------
= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}

-----------------------------------------------------------------------------------
Combine to single fraction
-----------------------------------------------------------------------------------

= \dfrac{1}{4(x+2)^2}



4 0
3 years ago
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