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abruzzese [7]
2 years ago
15

Helppppppppppppppppppppp

Mathematics
1 answer:
mojhsa [17]2 years ago
7 0

Answer:

Step-by-step explanation:

17.D

18.A

Number 18,l am trying

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How many arrangements can be made using 2 letters of the word HYPERBOLAS if no letter is to be used more than once?
alisha [4.7K]

Answer:

90 arrangements

Step-by-step explanation:

Since there are no repititions of letters, there are unique  10 letters in total.

THe number of arrangements would be 2 permutation 10. We need the formula for permutation. That is:

nPr=\frac{n!}{(n-r)!}\\

Now, n = 10 [total] and r is 2, so we have:

nPr=\frac{n!}{(n-r)!}\\\\_{10}P_{2}=\frac{10!}{(10-2)!}\\=\frac{10!}{8!}\\=\frac{10*9*8!}{8!}\\=10*9\\=90

So, there can be 90 arrangements

3 0
3 years ago
What’s the answer please hurry up
kramer

Answer:

63

Step-by-step explanation:

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3 years ago
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aleksklad [387]

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4 0
3 years ago
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How do you solve<br> 25n=70
alisha [4.7K]
You want to do to one side the same thing you do to the other side.

In order to get the n by itself you divide the 25n by 25. But in order to not change the answer you need to do the same to the 70.

\frac{25n}{25} =  \frac{70}{25}

so n=\frac{70}{25} which can be reduced to \frac{14}{5}

so n=\frac{14}{5}
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Answer:

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Step-by-step explanation:

is this right or wrong?

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