Answer:
Its the 2nd one
Step-by-step explanation:
Simplify the exponents and then multiply
Answer:
On the left... True
On the right... False
Step-by-step explanation:
To solve this problem you must apply the proccedure shown below:
1. You have the following logarithm:
<span>log(2)n=4
2. Therefore, you con rewrite it as below:
loga(b)=logb/loa
</span>
3. Therefore, you have:
log(2)n=4⇒log(n)/log(2)=4
4. Then, you obtain:
log(n)=4log(2)
5. Therefore, as you can see, the answer for the exercise shown above is the last option, which is:
log(n)=4log(2)
k, n - integers
2k+1 - an odd integer
2n+1 - another odd integer
The product of them:
(2k + 1)(2n + 1) =
= 4kn + 2k + 2n + 1 =
= 2(2kn + k + n) + 1
The product of integers (2kn) is integer
and the sum of them (2kn+k+n) also is integer
So (2k + 1)(2n + 1) = 2(2kn + k + n) + 1 is an odd integer
The first four-term of the sequence is found by the given equation 
is given as 144, 36, 9, and 9/4.
<h3>What is a sequence?</h3>
A sequence is a list of elements that have been ordered in a sequential manner, such that members come either before or after.
The given equation will be
And
For n = 4, we have
For n = 3, we have
For n = 2, we have
More about the sequence link is given below.
brainly.com/question/21961097
