Plz help me i will give 50 points,
1 answer:
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Answer:
A.
General Formulas and Concepts:
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] sinθ = opposite over hypotenuse
Step-by-step explanation:
<u>Step 1: Define</u>
sin 30°
<u>Step 2: Solve</u>
Since sin is opposite over hypotenuse, we need to find the length of the opposite leg of the angle and the length of the hypotenuse.
Given the triangle and it's values, the opposite leg to the 30° angle is 1 and the hypotenuse is 2.
Substituting it into sin, we have:
sin 30° = 1/2 = 0.5
∴ our answer is A.
The graph looks like this, on the enclosed pic:
One feature is that it's periodic and torn (has cut-off points), meaning the domain is the same as in case of tan(x): x€R and x =/= π/2+πn.
The range equals the range of arcsin(x): -π/2<=y<=π/2 OR y€[-π/2;π/2]
Hope could understand and if it helped! :)
One feature is that it's periodic and torn (has cut-off points), meaning the domain is the same as in case of tan(x): x€R and x =/= π/2+πn.
The range equals the range of arcsin(x): -π/2<=y<=π/2 OR y€[-π/2;π/2]
Hope could understand and if it helped! :)