Answer:
Another allele frequency = 17%
Explanation:
Given:
Allele A has a frequency = 83 percent
Find:
Another allele frequency
Computation:
Sum of percent = 100%
So,
Another allele frequency = 100% - 83%
Another allele frequency = 17%
Answer:
C) 2.0 kb
Explanation:
It is given that out of the 4 nucleotides A, T, C & G each one has equal probability to occur at any position on the DNA molecule which simply means that the probability of occurrence of any nucleotide at a position is 1/4.
Also, it is given that probability of occurrence of either A or T at 3rd position is equal which means that the probability at that particular position will be 2/4 = 1/2.
Now, GA(A/T)TC is the DNA sequence where Restriction enzyme HinfI cleaves so the total probability of an average HinfI cleavage fragment will be = 1/4 x 1/4 x 1/2 x 1/4 x 1/4 = 0.00195 = 0.2 i.e. 2 kb.
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