Answer:

Step-by-step explanation:
We're going to have to work backwards.
The sum of 4 and k is
.
Half is simply that divided by 2.

Now, we'll subtract 8 from it.

Bam!
<h3>C</h3>
f(x) does have an inverse function since it does pass the horizontal line test
Answer:
A
Step-by-step explanation:
Given
y - 2x - 8 = 0 ( add 2x + 8 to both sides )
y = 2x + 8 → (1)
y² + 8x = 0 → (2)
Substitute y = 2x + 8 into (2)
(2x + 8)² + 8x = 0 ← expand left side using FOIL and simplify
4x² + 32x + 64 + 8x = 0
4x² + 40x + 64 = 0 ( divide through by 4 )
x² + 10x + 16 = 0 ← in standard form
(x + 8)(x + 2) = 0 ← in factored form
x + 8 = 0 ⇒ x = - 8
x + 2 = 0 ⇒ x = - 2
Substitute these values into (1) for corresponding values of y
x = - 8 : y = 2(- 8) + 8 = - 16 + 8 = - 8 ⇒ P (- 8, - 8)
x = - 2 : y = 2(- 2) + 8 = - 4 + 8 = 4 ⇒ Q (- 2, 4 )
Calculate the length of PQ using the distance formula
PQ = 
with (x₁, y₁ ) = P (- 8, - 8) and (x₂, y₂ ) = Q (- 2, 4 )
PQ = 
= 
= 
= 
= 
= 
=
× 
= 6
→ A
Answer:
2 by 2
Step-by-step explanation:
Since, given matrix has 2 rows and 2 columns.
So, Its a 2 by 2 order matrix.
Given the coordinates of the image of line segment RT to be R'(-2,-4) and T'(4.4), if the image produced was dilated by a scale factor of 12 centered at the origin, to get the coordinate of the end point, we will simply multiply the x and y coordinates of by the factor of 12 as shown:
For R' with coordinate R'(-2,-4), the coordinates of endpoint of the pre-image will be:
R = 12R'
R = 12(-2, -4)
R = (-24, -48)
For T' with coordinate T'(4,4), the coordinates of endpoint of the pre-imagee will be:
T = 12T'
T = 12(4, 4)
T = (48, 48)
Hence the coordinate of the endpoint of the preimage will be at R(-24, -48) and T(48, 48)