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iren [92.7K]
3 years ago
6

A group pre-orders 12 tickets for a sightseeing tour, even though they don't have the money to pay for them yet. Each ticket cos

ts $32, so the debt for one ticket is - $32. The tour
company adds a $20 fee for the entire order. Including the fee, which number represents the total debt?
- $624
- $384
-$364
-$404
Mathematics
1 answer:
Sav [38]3 years ago
8 0
404 is the answer. if you add them all together
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Expression of "Eight less than half the sum of 4 and k” into symbol
jolli1 [7]

Answer:

\frac{4+k}{2} -8

Step-by-step explanation:

We're going to have to work backwards.

The sum of 4 and k is 4+k.

Half is simply that divided by 2.

\frac{4+k}{2}

Now, we'll subtract 8 from it.

\frac{4+k}{2} -8

Bam!

7 0
3 years ago
60 more points i believe
kondor19780726 [428]
<h3>C</h3>

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5 0
2 years ago
HELP ASAP ...........
dedylja [7]

Answer:

A

Step-by-step explanation:

Given

y - 2x - 8 = 0 ( add 2x + 8 to both sides )

y = 2x + 8 → (1)

y² + 8x = 0 → (2)

Substitute y = 2x + 8 into (2)

(2x + 8)² + 8x = 0 ← expand left side using FOIL and simplify

4x² + 32x + 64 + 8x = 0

4x² + 40x + 64 = 0 ( divide through by 4 )

x² + 10x + 16 = 0 ← in standard form

(x + 8)(x + 2) = 0 ← in factored form

x + 8 = 0 ⇒ x = - 8

x + 2 = 0 ⇒ x = - 2

Substitute these values into (1) for corresponding values of y

x = - 8 : y = 2(- 8) + 8 = - 16 + 8 = - 8 ⇒ P (- 8, - 8)

x = - 2 : y = 2(- 2) + 8 = - 4 + 8 = 4 ⇒ Q (- 2, 4 )

Calculate the length of PQ using the distance formula

PQ = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = P (- 8, - 8) and (x₂, y₂ ) = Q (- 2, 4 )

PQ = \sqrt{(-2-(-8))^2+(4-(-8))^2}

      = \sqrt{(-2+8)^2+(4+8)^2}

       = \sqrt{6^2+12^2}

       = \sqrt{36+144}

       = \sqrt{180}

       = \sqrt{36(5)}

       = \sqrt{36} × \sqrt{5}

        = 6\sqrt{5} → A

8 0
2 years ago
Please solve this question.
Fantom [35]

Answer:

2 by 2

Step-by-step explanation:

A = \begin{pmatrix} 1 & 2\\3 & 4\end{pmatrix}

Since, given matrix has 2 rows and 2 columns.

So, Its a 2 by 2 order matrix.

6 0
2 years ago
Read 2 more answers
The coordinates of the image of line segment RT are R'(-2,-4) and T'(4.4). The image was produced by a dilation with a scale fac
Daniel [21]

Given the coordinates of the image of line segment RT to be R'(-2,-4) and T'(4.4), if the image produced was dilated by a scale factor of 12 centered at the origin, to get the coordinate of the end point, we will simply multiply the x and y coordinates of by the factor of 12 as shown:

For R' with coordinate R'(-2,-4), the coordinates of endpoint of the pre-image will be:

R = 12R'

R = 12(-2, -4)

R = (-24, -48)

For T' with coordinate T'(4,4), the coordinates of endpoint of the pre-imagee will be:

T = 12T'

T = 12(4, 4)

T = (48, 48)

Hence the coordinate of the endpoint of the preimage will be at R(-24, -48) and T(48, 48)

6 0
1 year ago
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