The volume of the space not filled by the sphere is the difference between the volume of a cube with edge length 6 inches and the volume of a sphere with radius 3 inches.
<h3><u>Cube</u></h3>
The volume of a cube of edge length s is
... V = s³
When the edge length is 6 in, the volume is
... V = (6 in)³ = 216 in³
<h3><u>Sphere</u></h3>
The volume of a sphere with radius r is
... V = (4/3)π·r³
When the radius is 3 in, the volume is
... V = (4/3)π·(3 in)³ = 36π in³
<h3><u>Space</u></h3>
Then the volume of the space between the cube and the sphere is
... Vcube - Vsphere = 216 in³ - 36π in³ ≈ 102.9 in³ . . . . corresponding to choice C
Because you added 14 cards to your collection, we'll have to subtract that:
40 - 14 = 26
Knowing that 26 cards is half of your old card deck, we know that your old card deck is:
26*2 = 52
You have option b. 52 cards before.
Which coordinates are A and D?
What is the distance between angle C and F?
X^2 -5x -36 = x*x -9x+4x -9*4 = x(x-9) +4(x-9) = (x+4)(x-9)
so the second other factor is x+4 so hope that choice wan being x+4 than this will be right just you missed the sign pf plus
hope this will help you
