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hram777 [196]
3 years ago
14

Help I need the answer phone plz​

Mathematics
1 answer:
barxatty [35]3 years ago
6 0

Answer:

t>-4

I’m not sure if this is right

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Can someone help me with this two questions pls!!! I don't know how I can solve pls!
aivan3 [116]
20)

\bf ~~~~~~~~~~~~\textit{negative exponents}\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\\\
\textit{also recall that }a^{\frac{ n}{ m}} \implies  \sqrt[ m]{a^ n} 
\qquad \qquad
\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}
\\\\
-------------------------------

\bf \cfrac{(-54)^2}{\sqrt[3]{(-54)^5}}\implies \cfrac{(-54)^2}{(-54)^{\frac{5}{3}}}\implies (-54)^2(-54)^{-\frac{5}{3}}\implies (-54)^{2-\frac{5}{3}}
\\\\\\
(-54)^{\frac{6-5}{3}}\implies (-54)^{\frac{1}{3}}\implies \sqrt[3]{(-54)^1}\implies \sqrt[3]{(-54)}
\\\\\\
\begin{cases}
54=2\cdot 3\cdot 3\cdot 3\\
\qquad 2\cdot 3^3
\end{cases}\implies \sqrt[3]{-1\cdot 2\cdot 3^3 }\implies 3\sqrt[3]{-2}



22)

\bf -5\sqrt[3]{2x+3}=15\impliedby \textit{we first raise both sides by }^3
\\\\\\
(-5\sqrt[3]{2x+3})^3=(15)^3\implies (-5)^3(\sqrt[3]{2x+3})^3=3375
\\\\\\
(-125)(2x+3)=3375\implies 2x+3=\cfrac{3375}{-125}\implies 2x+3=-27
\\\\\\
2x=-30\implies x=-\cfrac{30}{2}\implies x=-15
4 0
3 years ago
Read 2 more answers
Find all polar coordinates of point P where P = ordered pair 6 comma negative pi divided by 5.
Allushta [10]

Answer:

P(6,-π/6) = (6, -π/6 + 2nπ) and P(-6,-π/6) = (-6, -π/6 + (2n+1)π)

Step-by-step explanation:

We need to find all polar coordinates of

P = (6,\frac{-\pi }{6})

The polar coordinates of any point can be reresented by (r,Ф)

where

(r,Ф) = (r, Ф+2nπ) where n is any integer and r is positive

and

(r,Ф) = (-r, Ф+(2n+1)π) where n is any integer and r is negative.

So, in the question given, r = 6 and Ф = -π/6

So, Polar coordinates will be:

P(6,-π/6) = (6, -π/6 + 2nπ) where where n is any integer and r is positive

and

P(-6,-π/6) = (-6, -π/6 + (2n+1)π) where n is any integer and r is negative.

6 0
3 years ago
Read 2 more answers
Solve for x. 2/x =2/6
olganol [36]
The answer is x = 6.

Here are the steps.

1. Simplify 2/6 to 1/3 ( 2/x = 1/3 ).

2. Multiply both sides by x ( 2 = 1/3x ).

3. Simplify 1/3x to x/3 ( 2 = x/3 ).

4. Multiply both sides by 3 ( 2 * 3 = x ).

5. Simplify 2 * 3 to 6 ( 6 = x ).

Now finally switch it up and the answer is x = 6.
7 0
3 years ago
Find the lateral area and surface area of a cone with a radius of 12 and a height of 21
marishachu [46]

Answer:

The Lateral Surface Area is 911.32 square unit and

Total Surface Area is 1361.7 square unit.

Step-by-step explanation:

For a given Cone

Radius (r) = 12

Height (h) = 21

<u>For Lateral Surface Area</u>

<h3><u>Formula</u><u>:</u> </h3>

A = πr√r² + h²

A = 3.14 × 12 × √(12)² + (21)²

A = 3.14 × 12 × √144 + 441

A = 3.14 × 12 × √585

A = 37.68 × 24.18

A = 911.32 square unit

Now,

<u>For</u><u> </u><u>Total</u><u> Surface Area</u>

<h3><u>Formula:</u></h3>

A = πrl + πr²

For Slant height (l)

l² = r² + h²

l² = (12)² + (21)²

l² = 144 + 441

l² = 585

l = 24.18

So,

A = πrl + πr²

A = πr(l + r)

A = 3.14 × 12 × (24.14 + 12)

A = 3.14 × 12 × 36.14

A = 1361.7 square unit

Thus, The <u>Lateral Surface Area</u> is 911.32 square unit and <u>T</u><u>otal Surface Area</u> is 1361.7 square unit.

<u>-TheUnknownScientist</u>

6 0
3 years ago
Read 2 more answers
Parker drove a total distance of 4 and 1 over 2 miles during the months of June and July. If Parker only drove 1 over 8 of a mil
never [62]

Answer: 4 and 1 over 2 ÷ 1 over 8


Step-by-step explanation:

Given that : Total distance drove by Parker =4 and 1 over 2 miles=4\frac{1}{2} miles

Distance drove by Parker each day = 1 over 8 mile=\frac{1}{8} mile

To find the total number of days , we need to divide the total distance by the distance drove by him in each day.

Thus, the number of days he went driving=4 and 1 over 2 ÷ 1 over 8

5 0
3 years ago
Read 2 more answers
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