We get tne n-th term with: tn=1/3tn-1
We know that the first term is t1=81, so 81=1/3t*1-1
81=1/3t-1
82=1/3t
82*3t=1
3t=1/82
t=1/82*3=1/246
The second term is: 1/
2*(1/246)*2)-1
We get the third term by replacing n with 3 and so on...
Answer:
Step-by-step explanation:
Given:
Solution:
We can solve for 
to make it less complicated.
Now we can solve for 
.
Answer:
pee
Step-by-step explanation:
It's some random dude's toilet
You know that t=0 and x=0, the car starts moving with a constant acceleration of 2.70m/s²
At the same time, a truck moving speed o 8.50 m/s passes the car
D=v.t (for the truck)
And d= v.t+1/2.a.t²(for the car)
v.t=1/2.a.t²
t=2.v/a
t=2.8.50 m/s/ 2.70 m/s²
17m/2.70=6.29
This mean that the distance is
D=v.t=8.50m/s.6.29= 53.465 m/s
The speed of the car is
Vcar=a.t
2.7m/s2×× 53.65
=144.34
Answer:
equilateral
Step-by-step explanation:
