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alexandr1967 [171]
3 years ago
6

Provide the first six terms of the following sequence: t1=81 tn=1/3tn-1

Mathematics
2 answers:
Andrews [41]3 years ago
8 0

We get tne n-th term with: tn=1/3tn-1

We know that the first term is t1=81, so 81=1/3t*1-1

81=1/3t-1

82=1/3t

82*3t=1

3t=1/82

t=1/82*3=1/246

The second term is: 1/

2*(1/246)*2)-1

We get the third term by replacing n with 3 and so on...

Mandarinka [93]3 years ago
7 0

Answer:

Through the window and under the door, It covers the walls and coats the floor.

Step-by-step explanation:


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SSSSS [86.1K]

Answer:

Teresa drive <u>90 miles</u> on Tuesday.

Step-by-step explanation:

Given:

Teresa drove on Monday, Tuesday and Wednesday.

On monday her driving distance was 120 miles.

The ratio of Wednesdays distance is 3/5.

The ratio of Wednesdays distance to Tuesday's distance is 5/4.

Now, to find the miles Teresa drive on Tuesday:

Teresa driving distance on Monday was = 120 miles.

Her driving distance on Wednesday is = \frac{3}{5}\ of\ 120.

=\frac{3}{5} \times 120\\\\=0.6\times 120\\\\=72\ miles.

Now, her driving distance on Tuesday is:

\frac{5}{4} \ of\ 72\\\\=\frac{5}{4} \times 72\\\\=1.25\times 72\\\\=90\ miles.

Therefore, Teresa drive 90 miles on Tuesday.

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