3 years ago

Provide the first six terms of the following sequence: t1=81 tn=1/3tn-1

Mathematics

2 answers:

Andrews [41]3 years ago

8 0

We get tne n-th term with: tn=1/3tn-1

We know that the first term is t1=81, so 81=1/3t*1-1

81=1/3t-1

82=1/3t

82*3t=1

3t=1/82

t=1/82*3=1/246

The second term is: 1/

2*(1/246)*2)-1

We get the third term by replacing n with 3 and so on...

Mandarinka [93]3 years ago

7 0

Answer:

Through the window and under the door, It covers the walls and coats the floor.

Step-by-step explanation:

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