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allochka39001 [22]
3 years ago
15

Marcos invited 33 guests to his party. So far, 8 guests have replied "will attend" and 9 guests have replied "will not attend".

How many guests (g) still need to reply?
Mathematics
2 answers:
Nikitich [7]3 years ago
8 0

Answer:

16 people haven't replied

Step-by-step explanation:

Add 9 + 8 = 17 and subtract 33 - 17 = 16

If this helps

myrzilka [38]3 years ago
5 0

Answer:

16

Step-by-step explanation:

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Gala2k [10]

Answer:

Part A= $21.35 || Part B= $4.37

Step-by-step explanation:

That's how money works.

4 0
3 years ago
Read 2 more answers
Nadia is ordering cheesecake at a restaurant, and the server tells her that she can have up to five toppings: caramel, whipped c
Nesterboy [21]

Answer:

The probability that Nadia gets just caramel, butterscotch sauce, strawberries, and hot fudge is P =  1/32 = 0.03125

Step-by-step explanation:

There are up to 5 toppings, such that the toppings are:

caramel

whipped cream

butterscotch sauce

strawberries

hot fudge

We want to find the probability that,  If the server randomly chooses which toppings to add, she gets just caramel, butterscotch sauce, strawberries, and hot fudge.

First, we need to find the total number of possible combinations.

let's separate them in number of toppings.

0 toppins:

Here is one combination.

1 topping:

here we have one topping and 5 options, so there are 5 different combinations of 1 topping.

2 toppings.

Assuming that each topping can be used only once, for the first topping we have 5 options.

And for the second topping we have 4 options (because one is already used)

The total number of combinations is equal to the product between the number of options for each topping, so here we have:

c = 4*5 = 20 combinations.

But we are counting the permutations, which is equal to n! (where n is the number of toppings, in this case is n = 2), this means that we are differentiating in the case where the first topping is caramel and the second is whipped cream, and the case where the first topping is whipped cream and the second is caramel, to avoid this, we should divide by the number of permutations.

Then the number of different combinations is:

c' = 20/2! = 10

3 toppings.

similarly to the previous case.

for the first topping there are 5 options

for the second there are 4 options

for the third there are 3 options

the total number of different combinations is:

c' = (5*4*3)/(3!) = (5*4*3)/(3*2) = 10

4 toppings:

We can think of this as "the topping that we do not use", so there are only 5 possible toppings to not use, then there are 5 different combinations with 4 toppings.

5 toppings:

Similar to the first case, here is only one combination with 5 toppings.

So the total number of different combinations is:

C = 1 + 5 + 10 + 10 + 5 + 1 = 32

There are 32 different combinations.

And we want to find the probability of getting one particular combination (all of them have the same probability)

Then the probability is the quotient between one and the total number of different combinations.

p = 1/32

The probability that Nadia gets just caramel, butterscotch sauce, strawberries, and hot fudge is P =  1/32 = 0.03125

8 0
2 years ago
(20n^2+N^3+10n^2) /10N^2
kirill115 [55]
Combine like terms:
n^3 + 20n^ + 10n^2
= n^3 + 30n^

Divide:
=n^3 + 30n^2/10n^2

Factor:
=n^2n + 30n^2
=n^(n + 30)
= 2^2(n + 30)/10n^2

Cancel the common factor n^2:
=n + 10/10

3 0
3 years ago
About 56% of the 2553 students are in rolled in at least one honors classes how many students are in rolled in an honors class
levacccp [35]

Answer:

1430 students

Step-by-step explanation:

5 0
3 years ago
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Please I beg you! Please need help, I can pay you! From PayPal if you help me!!!
Naddika [18.5K]

Answer:

lol how much??????.......

5 0
3 years ago
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