What is 21/49 in simplist from

Mathematics

1 answer:

ad-work [718]3 years ago

8 0

If you divide 21/49 by 7 you get 3/7

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Find r if 0=pi/6 rad sector 64m^2

kap26 [50]

Given:

Area of a sector = 64 m²

The central angle is $\theta=\dfrac{\pi}{6}$ .

To find:

The radius or the value of r.

Solution:

Area of a sector is:

$A=\dfrac{1}{2}r^2\theta$

Where, r is the radius of the circle and $\theta$ is the central angle of the sector in radian.

Putting $A=64,\theta=\dfrac{\pi}{6}$ , we get

$64=\dfrac{1}{2}r^2\times \dfrac{\pi}{6}$

$64=\dfrac{\pi}{12}r^2$

$64\times \dfrac{12}{\pi}=r^2$

$\dfrac{768}{\pi}=r^2$

Taking square root on both sides, we get

$\sqrt{\dfrac{768}{\pi}}=r$

$16\sqrt{\dfrac{3}{\pi}}=r$

Therefore, the value of r is $16\sqrt{\dfrac{3}{\pi}}$ m.

6 0

3 years ago

What is the slope of a line perpendicular to the line whose equation is Y=2x+5?

Oksanka [162]

B. slope is -1/2

This is because the m-value aka the slope is always the reciprocal if the line is perpendicular

8 0

3 years ago

Given that sin(90 -5ϴ) = Cos(180 - ϴ), Find the value of ϴ<br>

lilavasa [31]

Answer:

30°

Step-by-step explanation:

$\because \: \sin(90 \degree - \theta) = \cos \theta \\ \therefore \: \sin(90 \degree - 5 \theta) = \cos 5\theta....(1) \\ \\ \sin(90 \degree - 5 \theta) = \cos(180 \degree - \theta)...(2) \\ from \: (1) \: and \: (2) \\ \cos 5\theta = \cos(180 \degree - \theta) \\ 5 \theta = 180 \degree - \theta \\ 5 \theta + \theta= 180 \degree \\ 6\theta= 180 \degree \\ \theta = \frac{180 \degree}{6} \\ \\ \huge \red{ \boxed{\theta = 30 \degree}}$