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3 years ago

Given: ∠AOB is a central angle and ∠ACB is a circumscribed angle.

Mathematics

2 answers:

Novosadov [1.4K]3 years ago

4 0

Answer:

We are given that angle AOB is a central angle of circle O and that angle ACB is a circumscribed angle of circle O. We see that AO ≅ BO because

✔ all radii of the same circle are congruent.

We also know that AC ≅ BC since

✔ tangents to a circle that intersect are congruent.

Using the reflexive property, we see that

✔ side CO is congruent to side CO.

Therefore, we conclude that △ACO is congruent to △BCO by the

✔ SSS congruence theorem.

please mark brainliest.... hope you have a great day ! XD

algol133 years ago

3 0

Answer:

Step-by-step explanation:

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one teacher wants to give each student 7/8 of a slice of pizza. If the teacher has 7 slices of pizza then how many students will

Crazy boy [7]

Answer:

The teacher can hand out pizza to 8 students.

Step-by-step explanation:

To find how many slices of pizza the teacher can hand out , you can divide 7 by 7/8 and round down the nearest whole number.

7 ÷ 7/8 = 8

8 is already a whole number. No need to round down.

The teacher can hand out pizza to 8 students.

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3 years ago

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3 years ago

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1 point

swat32

Answer:

$\log_{10}(147) = 2.1673$

Step-by-step explanation:

Given

$\log_{10} 3 = 0.4771$

$\log_{10} 5 = 0.6990$

$\log_{10} 7= 0.8451$

$\log_{10} 11 = 1.0414$

Required

Evaluate $\log_{10}(147)$

Expand

$\log_{10}(147) = \log_{10}(49 * 3)$

Further expand

$\log_{10}(147) = \log_{10}(7 * 7 * 3)$

Apply product rule of logarithm

$\log_{10}(147) = \log_{10}(7) + \log_{10}(7) + \log_{10}(3)$

Substitute values for log(7) and log(3)

$\log_{10}(147) = 0.8451 + 0.8451 + 0.4771$

$\log_{10}(147) = 2.1673$

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2 years ago

What is the equation of the line that passes through the point (-4,2) and has a slope of 1/4

zubka84 [21]

Step-by-step explanation:

Equation of line is y-y1 = m(x-x1), where m is the slope and (x1,y1) is the given point.

y-2 = 1/4*(x-(-4))

y-2 = 1/4 * (x+4)

4*(y-2) = x+4

Equation of the line is,

x-4y = -12

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2 years ago

Ann car can go 117 miles on 3 gallons of gas. During a drive last weekend, Ann used 8 gallons of gas. How far did she drive?

Nitella [24]

Answer:

Ann drove 312 miles in 8 gallons.

Step-by-step explanation:

Distance covered by Ann's car = 117 miles

Gallons of gas spent by Ann's car to cover 117 miles = 3 gallons

Unit rate = 117 miles / 3 gallons

= 39 miles per gallon

so Ann's car can go 39 miles in one gallon of gas.

Given that Ann used 8 gallons of gas.

Therefore,

Distance covered by Ann's car in 8 gallons = 39 × 8

= 312 miles

Therefore, Ann drove 312 miles in 8 gallons.

6 0

3 years ago