Answer:
y = - 2(x + 4)² + 6
Step-by-step explanation:
The equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Here (h, k ) = (- 4, 6 ) , thus
y = a(x - (- 4) )² + 6 , that is
y = a(x + 4)² + 6
To find a substitute (- 2, - 2) into the equation
- 2 = a(- 2 + 4)² + 6 ( subtract 6 from both sides )
- 8 = a(2)² = 4a ( divide both sides by 4 )
- 2 = a , thus
y = - 2(x + 4)² + 6 ← equation in vertex form
R = [ 3 7 -2 -11 ]
for 4R, you just have to multiply each by 4
4R = [ ( 3 x 4 ) ( 7 x 4 ) ( -2 x 4 ) ( -11 x 4 ) ]
4R = [ 12 28 -8 -44 ]
I'm pretty sure you are looking for factored forms as an equivalent equation, so here is how you do it.
This equation would be solved by difference of squares. 16, x^4, and 81 are all perfect squares ( which means that it is a number multiplied by itself, 16 is 4 x4 for example). So the first thing you want to do is recall the formula which is
(a^2 - b^2) = (a - b)*(a + b)
(16x^4 - 81)= 0
Find the sq. root of 16 which is 4, and of x^4 which is x^2, and 81 which is 9. Now re write it in the (a - b)*(a + b) format. ----> (4x^2 - 9)*(4x^2 + 9) = 0
Answer:
Given by what graph? I don't see a graph here...
Step-by-step explanation:
Answer:
1/2 one half
Step-by-step explanation:
