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ahrayia [7]
3 years ago
8

Can someone help me please? :(

Mathematics
2 answers:
Drupady [299]3 years ago
8 0

Answer:

1.). B(0,4)

2). G(-4,3)

3). H(2,0)

4). A(0,-4)

Step-by-step explanation:

How I got the answer:

To find coordinates, you look for the number in x-axis first and then the number in y-axis.

Like the coordinate for 1 is:

x-axis – 0

y-axis – 4

which is (0,4).

The coordinate for 2 is:

x-axis – -4

y-axis – 3

which is (-4,3).

The coordinate for 3 is:

x-axis – 2

y-axis – 0

which is (2,0).

Like the coordinate for 1 is:

x-axis – 0

y-axis – -4

which is (0,-4).

polet [3.4K]3 years ago
4 0

Answer:

1. B (0,4)

2. G ( -4,3)

3. H (2,0)

4.A (0,-1)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
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Evaluate AB whenA 13 -2 6 and B4O A)233 2 6O B) 12 8 246 4-123 2 -6O C) 128 246 4 12O D) No solution
kiruha [24]
The answer is A) -23

A is a 1x3 Matrix while B is 3x1 Matrix. Since A has the same number of rows as that of the number of columns of B, they can be multiplied. A has 1 row and B has 1 column. So, their products is a 1x1 Matrix. 
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7 0
4 years ago
I need help on this pls answer
Anastaziya [24]

Answer:

144500

Step-by-step explanation:

(1.7 x 10^4) x (8.5 x 10^-2)

= (1.7 x 10000) x (8.5 x 0.01)

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=17000/1 x 17/200

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6 0
2 years ago
What is the Gcf of the number below
never [62]

9514 1404 393

Answer:

  b.  60

Step-by-step explanation:

The list of factors is 2, 3, 5, 7. The list of common factors is 2, 3, 5. The lowest exponents on those factor are ...

  2^2 × 3^1 × 5^1 = 60

The GCF of 720 and 2100 is 60.

_____

<em>Additional comment</em>

You can verify this using Euclid's method of finding the GCF.

  2100/720 = 2 r 660

  720/660 = 1 r 60

  660/60 = 11 r 0 . . . . 60 is the GCF

Find the remainder from the division. If it is zero, the divisor is the GCF. If it is non-zero, replace the largest number with the remainder, and repeat.

7 0
3 years ago
What is step two in the problem solving process
miskamm [114]
Hey there,
It would be devising a plan

Hope this helps :))

<em>~Top♥</em>
6 0
3 years ago
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