<span>13⁄41 + 27⁄82 = 26/82 + 27/82 = 53/82
3 5/24 + 6 7/24 + 4 9/24 = 13 20/24 = 13 5/6
</span><span>5 2⁄3 + 29⁄69 + 6 21⁄23 = 5 46/69 + 29/69 + 6 63/69 = 11 138/69 = 13
</span>
<span>3 9⁄10 + 4⁄9 + 7⁄45 + 4 = 3 81/90 + 40/90 + 14/90 + 4 = 7 135/90 = 8 1/2
</span><span>6 – 7⁄15 = 5 15/15 - 7/15 = 5 6/15
</span><span>11 3⁄8 – 7⁄8 = 10 11/8 - 7/8 = 10 4/8 = 10 1/2
</span><span> 7 1⁄6 – 3 4⁄9 = 7 9/54 - 3 18/54 = 6 63/54 - 3 18/54 = 3 45/54 = 3 5/6
</span>
<span>5 3⁄8 – 3 2⁄5 = 5 15/40 - 3 16/40 = 4 55/40 - 3 16/40 = 1 39/40</span>
Answer:
your answer to that would be 5 other Geographic Square
ABCD 1234 AEIOU = meow meow i’m not a cow who who
Answer:
See below, please!
Step-by-step explanation:
We can set up a system of equations to model this problem. Let's consider the student's ticket as x, and y for the adult ticket.
So since the student ticket is $1.50, and adult is $4, we can set up the following equation: 
, since they collected $5050 total.
We can set up another equation modeling the number of people who came to the game. This would be x+y=2200.
Solve this, and we get x= 1500 and y=700. So, they sold 1500 student tickets and 700 adult tickets.
Hope this helped!
