Most of the energy for living organisms in food chains and webs is provided by which organisms

In part A, you analyzed genes that contribute to two diseases. (cystic fibrosis and muscular dystrophy) How can scientists use t

N76 [4]

Answer:

By designing suitable gene therapies in order to restore target gene expression.

Explanation:

Cystic fibrosis and muscular dystrophy are inherited genetic disorders associated with serious health problems. Cystic fibrosis is caused by mutations in the gene that encodes for the cystic fibrosis transmembrane conductance regulator (CFTR) protein, and it is a condition associated with abnormal production of sticky mucus that leads to problems in the lungs and the digestive systems. On the other hand, muscular dystrophy is produced by mutations in genes localized on the X chromosome such as, for example, the gene 'dystrophin'. Gene therapy is an experimental approach used to compensate abnormal gene function by introducing exogenous genetic material and thus restore their altered protein products. Consequently, personalized gene therapies can be useful to treat inherited disorders such as cystic fibrosis and muscular dystrophy.

4 0

3 years ago

You are doing research on nervous system diseases; particularly, one that dissolves lipids. What part of the neuron would you ex

ExtremeBDS [4]

Answer:

Myelin sheath

Explanation:

...........

3 0

3 years ago

For fertilization to occur in humans, only one sperm is needed to weaken the barrier that surrounds the egg.

photoshop1234 [79]

Answer:

False

Explanation:

Approximately 200 out of 200 million sperms ejaculated during intercourse reach the general vicinity of the egg. They sperms must undergo capacitation during which dilute inhibitory factors fluids of the female reproductive tract weaken the membrane of the sperm head so that head of the sperm can be broken easily when it came in contact with the egg.

The first sperm to reach an egg isn’t the one to fertilize it because the egg is surrounded by a gelatinous membrane called the zona pellucida. Outside this layer, a layer of small granulosa cells also present.

Therefore, it requires numerous sperm to clear a path through these barriers before one of them can penetrate the egg and fertilize it.

8 0

4 years ago

2. Dominant trait: cleft chin (C) Mother’s gametes: Cc

andre [41]

.2. Offspring Genotypes will be Cc or cc.

Offspring phenotypes : Cleft chin or no cleft chin.

% chance child will have cleft chin: 50%

3. % chance child will have arched feet: 25%

4. % chance child will have blonde hair: 50%

5. % chance child will have normal vision: 25%

Explanation:

CASE 1 :

Dominant trait: cleft chin (C)

Recessive trait: lacks cleft chin (c)

Father’s gametes: cc

Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents= $\frac{1}{2}C + \frac{1}{2} c$ ........(i)

Gametes of cc parents = $\frac{1}{2}c + \frac{1}{2}c$ .........(ii)

Combining (i) and (ii) we get,

$\frac{1}{2} Cc + \frac{1}{2} cc$

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin = $\frac{0.5}{1}$ ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

A from mother, a from father =Aa

a from mother, A from Father = Aa

a from mother, a from father = aa

Gametes of Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

Gametes of other Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

..................................................................................

$\frac{1}{4} AA + \frac{1}{4} Aa$

+ $\frac{1}{4} Aa$ + $\frac{1}{4} aa$

..........................................................................................

$\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa$

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = $\frac{0.25}{1}$ × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive (bb)

Father’s gametes: Heterozygous (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in half Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous (Ff)

Father’s gametes: Heterozygous (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF then phenotype farsightedness

Genotype Ff then phenotype farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

3 0

3 years ago

Provides energy in the form of atp endoplasmic reticulum (er) for a storage reservoir and transport channel within the cell?

almond37 [142]

This form of providing energy for the storage and transport within the cell is called as Mitochondria. The energy production is done threw respiration and help regulate the cellular metabolism. Mitochondria are organelle that is present in the cytoplasm, not nucleus. Exercising your body can boost the density of mitochondria.

6 0

4 years ago