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3 years ago

Is the data skewed, symmetrical, or none?

Mathematics

2 answers:

notka56 [123]3 years ago

8 0

This data is skewed to the right. It is skewed to the right because a right seemed histogram has a peak in the left most center. It is also is skewed data because if the data was symmetrical you would be able to “cut it in half” and it will still be the same on both sides. You can also tell because if you were to find the mean, mode and median you will find that the mean is actually larger than the median

Feliz [49]3 years ago

6 0

Answer:

The data is skewed to the right.

Step-by-step explanation:

It's skewed to the right bc you can see it slowly coming from the left and the it goes up and then down again. So I think it's skewed it's the right...!

PLS MARK BRAINLIEST!!!!!

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3 years ago

Read 2 more answers

F(x) = x^2. What is g(x)?

Vikki [24]

Answer:

A. g(x)=1/2x²

Step-by-step explanation:

Given:

f(x)=x²

We have to find g(x)

Since, we are given that g(2)=2

1. g(x)=1/2x²

x=2

g(x)=1/2(2)²

=1/2(4)

=4/2

2. g(x)=1/4x²

x=2,

g(x)=1/4(2)²

=1/4(4)

=4/4

3. g(x)= 2x²

at x=2,

g(x)=2(2)²

=2(4)

4. g(x)=(1/2x)²

x=2

g(x)={1/2(2)}²

=(1/4)²

=1/16

A. g(x)=1/2x² is the answer

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4 years ago

Solve for x in terms of b and c: 2x - b = c

Amiraneli [1.4K]

2x - b = c

Add b to both sides.

2x = c + b

Divide both sides by 2.

x = $\frac{c+b}{2}$

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3 years ago

A robot has a straight arm 20 inches long that can rotate about the origin of a coordinate system. If the robot’s hand is locate

scoundrel [369]

Answer:

The location of the robots hand after rotating 45° counterclockwise from (-20, 0) in inches is (-14.14, 14.14)

The location of the robots hand after rotating 45° clockwise from (-20, 0)) in inches is (-14.14, -14.14)

Step-by-step explanation:

The initial location of the robots hand = (-20, 0)

The angle through which the robot rotates his hand = 45°

∴ We have the length of the robots hand = 20 inches

We note that (-20, 0) is in the 2nd Quadrant

The location of the robots hand after rotating 45° counterclockwise = 135°

Therefore, the location of the robots hand after the rotation = (20×cos(135°), 20×sin(135°)) = (-10·√2, 10·√2) = (-14.14, 14.14)

The location of the robots hand after rotating 45° clockwise from (-20, 0) = 225°

Therefore, the location of the robots hand after the rotation = (20×cos(225°), 20×sin(225°)) = (-10·√2, -10·√2) = (-14.14, -14.14)

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3 years ago

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Answer:

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