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djyliett [7]
3 years ago
5

2. Cross out the equations that are NOT linear functions.

Mathematics
2 answers:
wel3 years ago
8 0

Welcome to the concept of the maths.

Here, we can see, that Linear equation always have highest power or degree of its variable as '1' ,

thus here, y = 3/x has degree as -1 and y = x^2 +5 has degree 2 ,

hence,

The equations that are NOT linear are

2.) y = 3/x and 5.) y = x^2 + 5

Airida [17]3 years ago
4 0
Y=4 is the correct I think
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Usimov [2.4K]
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6 0
3 years ago
A rectangle measures 16 cm by 4 cm. It has the same area as a square. Find the perimeter of the square.
Elis [28]

ok ... in this situation... we need to find the area of the rectangle first as it is equal to the area of square .

so .... area of rectangle = l×b= 16×4

= 64 ∴area of square = 64

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7 0
3 years ago
an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a
viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is;  \mathbf{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft  is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the  rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at  a time t and r = radius of the cone shaped at a time t

Then the similar triangles  ΔOCD and ΔOAB is as follows:

\dfrac{h}{r}= \dfrac{20}{8}    ( similar triangle property)

\dfrac{h}{r}= \dfrac{5}{2}

\dfrac{h}{r}= 2.5

h = 2.5r

r = \dfrac{h}{2.5}

The volume of the water in the tank is represented by the equation:

V = \dfrac{1}{3} \pi r^2 h

V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h

V = \dfrac{1}{18.75} \pi \ h^3

The rate of change of the water depth  is :

\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

Since the water is drained  through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

\dfrac{dv}{dt}= - 4  \ ft^3/sec

Therefore,

-4 = \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

the rate of change of the water at depth h = 10 ft is:

-4 = \dfrac{ 100 \ \pi }{6.25}\  \dfrac{dh}{dt}

100 \pi \dfrac{dh}{dt}  = -4 \times 6.25

100  \pi \dfrac{dh}{dt}  = -25

\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi}

Thus, the rate of change of the water depth when the water depth is 10 ft is;  \mathtt{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

4 0
4 years ago
Can u guys help me pls ill give u 20 points
Veseljchak [2.6K]

Answer:

Its either L or N im not sure but if i had to guess out of the two i think its L.

Step-by-step explanation:

6 0
3 years ago
MULTIPLE STEP-writing equations in slope form/intercept form
mr Goodwill [35]

Answer:

y=x+8

Step-by-step explanation:

y= x+8

8 is your y intercept

and your slope is 1 but it's x

6 0
2 years ago
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