Y-y1=m(x-x1)
a point on the line is (x1,y1) and the slope is m

so
slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
so

points (-2,3) and (3,0)
slope is (0-3)/(3-(-2))=-3/(3+2)=-3/5
a point is (3,0) Or (-2,3)

so it could be
y-0=-3/5(x-3) or y-3=-3/5(x-(-2)) which is equal to y-3=-3/5(x+2)
that's the answer
B is answer

7 0

3 years ago

Please Help ASAP I’m confused

lana66690 [7]

Answer: B. 200ft

Step-by-step explanation:

Pythagorean theorem so a^2+b^2+c^2 or 120^2+160^2=c^2 where c is the value for the diagonal so solving for c to get 200

5 0

3 years ago

Plz write this on paper help me and send it❤️

vovangra [49]

Answer:

1. $27^{\frac{2}{3} } =9$

2. $\sqrt{36^{3} } =216$

3. $(-243)^{\frac{3}{5} } =-27$

4. $40^{\frac{2}{3}}=4\sqrt[3]{25} =4325$

5. Step 4: $(\frac{343}{27}) ^{-1} =\frac{27}{343}$

6. $D. -72cd^{7}$

Step-by-step explanation:

Use the following properties:

$a^{\frac{x}{y} } =\sqrt[x]{a^{y} }$

$\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}$

$a^{-n} =\frac{1}{a^{n} }$

$(xy)^{z} =x^{z} y^{z} \\\\$

$(x^{y}) ^{z} =x^{yz}$

$x^{y} x^{z} =x^{y+z}$

So:

1. $27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9$

2. $\sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36} \sqrt{36} =6*6*6=216$

3. $(-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27$

4. $40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325$