98^2 = (100-2)^2
Using (a-b)^2, we have
= (100)^2-2(100)(2)+(2)^2
= 10000-400+4
= 10004-400
= 9604
The answer is 9604.
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The answer to this is Complementary Angles.
The terminal side means that it's 16 to the right and 12 up. Which means that the triangle made from this has the sides of 16 and 12 and the hypotenuse is 20 units long. Theta, in this case, would have 16 as it's adjacent and 12 as it's opposite.
Therefore, using the Pythagorean identities:
<span>
</span>
Answer:
Option A
Step-by-step explanation:
Given:
- a. 3x-5= 3x + 5
- b. 3x-5= 3x - 5
- c. 3x - 5 = 2x+5
- d. 3x-5 = 2x + 10
To find:
- Which one of the linear equations have no solution.
Solution:
a) 3x-5= 3x + 5
Add 5 to both sides
3x-5= 3x + 5
3x - 5 + 5 = 3x + 5 + 5
Simplify
(Add the numbers)
3x - 5 + 5 = 3x + 5 + 5
3x = 3x + 5 + 5
(Add the numbers)
3x = 3x + 5 + 5
3x = 3x + 10
Subtract 3x from both sides
3x = 3x + 10
3x - 3x = 3x + 10 - 3
Simplify
(Combine like terms)
3x -3x = 3x + 10 - 3
0 = 3x + 10 - 3
(Combine like terms)
0 = 3x + 10 - 3
0 = 10
The input is a contradiction: it has no solutions
b) 3x-5= 3x - 5
Since both sides equal, there are infinitely many solutions.
c) 3x - 5 = 2x+5
Add 5 to both sides
3x = 2x + 5 + 5
Simplify 2x + 5 + 5 to 2x + 10
3x = 2x + 10
Subtract 2x from both sides
3x - 2x = 10
Simplify 3x - 2x to x.
x = 10
d) 3x-5 = 2x + 10
Add 5 to both sides
3x = 2x + 10 + 5
Simplify 2x + 10 + 5 to 2x + 15
3x = 2x + 15
Subtract 2x from both sides
3x - 2x = 15
Simplify 3x -2x to x.
x = 15
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Answer:
As you can see all c and d both have solutions, eliminating them as options. Option B has infinite solutions leaving Option A which has no solutions.
Therefore, <u><em>Option A</em></u> is the linear equation that has no solution.