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frosja888 [35]
3 years ago
4

The function C (t) = StartFraction 4 t Over t squared + 2 EndFraction models the cost per student of a field trip when x student

s go on the trip. How is the parent function On a coordinate plane, 3 curves are shown. One curve opens up and to the right in quadrant 1 and goes through (2, 4) and (4, 1). Another curve approaches x = negative 2 in quadrant 2, changes direction at (0, 0), and then decreases in quadrant 4 and approaches y = 2. The third curve opens down and to the left in quadrant 3 and goes through (negative 4, negative 1) and (negative 2, negative 4). transformed to create the function On a coordinate plane, 2 curves are shown. One curve opens up and to the left in quadrant 2 and goes through (negative 4, 8) and (negative 6, 6). Another curve opens down and to the right and goes through (negative 1, negative 3), (0, 0), and (6, 3).?
Mathematics
2 answers:
Maru [420]3 years ago
5 0

Answer:

The answer is "It is vertically stretched by a factor of 200 and shifted 10 units up".

Step-by-step explanation:

In this question, some data is missing that's why we define the correct choice only.

earnstyle [38]3 years ago
3 0

Answer:

C. It is vertically stretched by a factor of 200 and shifted 10 units up.

Step-by-step explanation:

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Suppose that the number of drivers who travel between a particular origin and destination during a designated time period has a
Bumek [7]

Answer:

0.381 is the probability that the number of drivers will be at most 18.                          

Step-by-step explanation:

We are given the following information in the question:

The number of drivers who travel between a particular origin and destination during a designated time period has a Poisson distribution with parameter μ = 20.

  • The Poisson distribution is the discrete probability distribution of the number of events occurring in a given time period, given the average number of times the event occurs over that time period.
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a) P(number of drivers will be at most 18)

Formula:

P(X =k) = \displaystyle\frac{\mu^k e^{-\mu}}{k!}\\\\ \mu \text{ is the mean of the distribution}

P( x \leq 18) =P(x=0) + P(x =1) + P(x = 2) + ... + P(x = 18)\\\\= \displaystyle\frac{20^0 e^{-20}}{0!} + \displaystyle\frac{20^1 e^{-20}}{1!} +...+ \displaystyle\frac{20^{18} e^{-20}}{18!}\\\\ = 0.381

Thus, 0.381 is the probability that the number of drivers will be at most 18.

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Solve for x.<br><br> x−1/4=38<br><br><br><br> Enter your simplified answer in the box.
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1. x - 1/4 = 3/8;
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