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MrRa [10]
3 years ago
15

What is the product of 2x -5 and 3x^2 + 5x - 7? Write your answer in standard form. A. Show your work. B. Is the product of 2x -

5 and 3x^2 + 5x -7 equal to the product of 5x - 2 and 3x^2 + 5x - 7? Explain your answer.
Mathematics
1 answer:
VikaD [51]3 years ago
6 0

Answer:

A)What is the product of 2x -5 and 3x^2 + 5x - 7? Write your answer in standard form.

6x³ - 5x² - 39x + 35 = 0

B. Is the product of 2x -5 and 3x^2 + 5x -7 equal to the product of 5x - 2 and 3x^2 + 5x - 7?

No it is not.

Step-by-step explanation:

A)What is the product of 2x -5 and 3x^2 + 5x - 7? Write your answer in standard form.

(2x - 5) (3x² + 5x - 7)

= 2x(3x² + 5x - 7) -5(3x² + 5x - 7)

= 6x³ + 10x² - 14x -15x² - 25x +35

Collecting like terms

= 6x³ +10x² - 15x² - 14x - 25x +35

= 6x³ - 5x² - 39x + 35

In standard form

6x³ - 5x² - 39x + 35 = 0

B. Is the product of 2x -5 and 3x^2 + 5x -7 equal to the product of 5x - 2 and 3x^2 + 5x - 7?

First we find the product of

5x - 2 and 3x² + 5x - 7?

(5x - 2) (3x² + 5x - 7)

5x(3x² + 5x - 7) -2(3x² + 5x - 7)

15x³ + 25x² - 35x - 6x² -10x + 14

Collect like terms

15x³+ 25x² - 6x² -35x - 10x + 14

15x³ + 19x² - 45x + 14 = 0

Hence, the product of 5x - 2 and 3x^2 + 5x - 7

= 15x³ + 19x² - 45x + 14 = 0

The product of 2x -5 and 3x^2 + 5x -7 = 6x³ - 5x² - 39x + 35 = 0

Comparing both products, we can see that

The product of 2x -5 and 3x^2 + 5x -7 ≠ the product of 5x - 2 and 3x^2 + 5x - 7

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AlladinOne [14]

Answer:

  • domain: all terms are defined for <em>all real numbers</em>
  • solution: x = 6

Step-by-step explanation:

Rewrite the equation as a single exponential. After taking the log, the solution becomes obvious.

5^{x-2}-7^{x-3}=7^{x-5}+11\cdot 5^{x-4}\\\\5^{x-2}-11\cdot 5^{x-4}=7^{x-3}+7^{x-5}\\\\5^{x-2}(1-11\cdot 5^{-2})=7^{x-3}(1+7^{-2})\\\\5^{x-2}\dfrac{14}{25}=7^{x-3}\dfrac{50}{49}\\\\1=\dfrac{2\cdot 7^{x-3}5^4}{2\cdot 5^{x-2}7^3}=\left(\dfrac{7}{5}\right)^{x-6}\\\\0=(x-6)\log(1.4)\\\\x=6

6 0
3 years ago
Which represents the solution to the absolute value equation? 3|2x+4|-1=11
larisa86 [58]
The first step for absolute value equations is to isolate the expression contained within the absolute value bars:

3|2x+4|-1 = 11
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2x+4 = 4

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3 years ago
LA DISTANCIA ENTRE LA TIERRA YLA LUNA ES DE 384 392 KM. LOS AUSTRONAUTAS DE LA APOLO XL SALIERON EL 16 DE JULIO DE 1969 DESDE EL
KengaRu [80]

Complete question :

la distancia entre la tierra y la luna es de 384 392 km. Los astronautas de la Apolo XL salieron el 16 de julio de 1969 desde el Centro Espacial Kennedy y al alcanzaron la orbita el 19 de julio de 1969. Suponiendo que cada dia recorrieron la misma cantidad de kilometros cuantos kilometros recorrieron por dia

Responder:

128130,66 kilometros

Explicación paso a paso:

Dado que:

Distancia entre la tierra y la luna = 384,392 km

Tiempo empleado = (19 de julio - 16 de julio) mismo año = 3 días

Velocidad = distancia / tiempo

El tiempo empleado es (3 * 24) = 72 horas

Por lo tanto,

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Dado que se supone que la distancia recorrida diariamente es la misma m:

El número de kilómetros recorridos por día:

5338,7777 kilómetros por hora * 24

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