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andrew11 [14]
3 years ago
6

Myra owns a car service that charges a $5 flat rate and an additional $0.50 per mile, which is represented by the equation y = 0

.5x + 5, where x is the number of miles and y is the total cost.
How much is the total cost for a car with 30 miles?
Mathematics
2 answers:
klasskru [66]3 years ago
6 0
Just substitute
0.5(30)+5 =20
Nataly [62]3 years ago
3 0
$20
Because it costs $0.50 per mile so 0.50 times 30 but then you have the 5$ flat rate.
0.50x30+5=20
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Please help me (math)<br><br> Is it A and B or just A? <br><br> Im 99% sure it is not C :)
PSYCHO15rus [73]
I’m pretty sure it’s a
5 0
3 years ago
An instructor gives her class the choice to do 7 questions out of the 10 on an exam.
Maksim231197 [3]

Answer:

(a) 120 choices

(b) 110 choices

Step-by-step explanation:

The number of ways in which we can select k element from a group n elements is given by:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

10C7=\frac{10!}{7!(10-7)!}=120

Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

(5C4)(5C3)=\frac{5!}{4!(5-4)!}*\frac{5!}{3!(5-3)!}=50

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10

So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:

50 + 50 + 10 = 110

6 0
3 years ago
Ricky Major
Assoli18 [71]

Answer:

Step-by-step explanation:

The diameter of each curved path is 200 feet. Since the two curved semi circular paths are equal, they would form a circle. It means that the distance around the two semi circular paths would be the circumference of the circle. Formula for determining the circumference of the circle is π × diameter. It becomes

200 × 3.14 = 628 feet

Total distance around the track would be

300 + 300 + 628 = 1228 feet

5280 feet = 1 mile

1228 feet = 1228/5280 = 0.23 mile

If he runs around the track exactly 15 times, it means that the number of miles covered is

0.23 × 15 = 3.45 miles

Since he will collect $4.50 for every mile he runs, the amount of money that he collected is

4.5 × 3.45 = $15.5

5 0
3 years ago
Which equation is part of solving the system by substitution? 4(y + 11)2 – 3y2 = 8 4(11 – y)2 – 3y2 = 8 4(y – 11)2 – 3y2 = 8 4(–
swat32

Answer:

4(11-y)^{2} -3y^{2}=8

Step-by-step explanation:

we have

x+y=11 ----> equation A

4x^{2} -3y^{2}=8 ----> equation B

Solve the system by substitution

step 1

isolate the variable x in the equation A

x=11-y ----> equation A1

step 2

Substitute the equation A1 in the equation B

4(11-y)^{2} -3y^{2}=8

Solve for y

3 0
3 years ago
Read 2 more answers
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