Answer:
Step-by-step explanation:
Given that,
f(3) = 2
f'(3) = 5.
We want to estimate f(2.85)
The linear approximation of "f" at "a" is one way of writing the equation of the tangent line at "a".
At x = a, y = f(a) and the slope of the tangent line is f'(a).
So, in point slope form, the tangent line has equation
y − f(a) = f'(a)(x − a)
The linearization solves for y by adding f(a) to both sides
f(x) = f(a) + f'(a)(x − a).
Given that,
f(3) = 2,
f'(3) = 5
a = 3, we want to find f(2.85)
x = 2.85
Therefore,
f(x) = f(a) + f'(a)(x − a)
f(2.85) = 2 + 5(2.85 - 3)
f(2.85) = 2 + 5×-0.15
f(2.85) = 2 - 0.75
f(2.85) = 1.25
Answer:
I think true im sorry if its not
Answer:
74
x
+
185
Step-by-step explanation:
Answer:
P = 64 cm
Step-by-step explanation:
<C = 150° - 90° = 60°
AB = AC
∠B = ∠C = 60° } => ΔABC = EQUILATERAL TRIANGLE =>
=> BC = 10 cm
P = 10cm + 8cm + 6cm + 10cm + 6cm + 6cm + 8cm + 10cm
P = 3x10cm + 2x8cm + 3x6cm
P = 30cm + 16cm + 18cm
P = 64 cm
