Answer:
Explanation:
1. If we enter to the BIOS we can enable or disable components, we can find the issue with this option.
2. In the BIOS we can set or reset power-on passwords, this option is really important to administrate our access and passwords.
3. We can change the date and time of the system, some troubles are only for that.
Answer:
<em>D Lan</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:
Use an opto coupler
Explanation:
Without knowing the context of your question, I can say that to eliminate effects of galvanic coupling, you an use an optical connection to transfer e.g., data.
import math as m
def print_word(N, W, retries = 4):
for _ in retries:
if(N > 100 or N < 0 or len(W) > 50):
print("Number is out of range or word is too large. Try again.")
new_word = str(input("New word: "))
new_num = int(input("New number: "))
if(new_num >= 0 and new_num <= 100 and len(W) <= 50):
for row in new_num:
print(new_word)
return "Thank you for your time!"
if(N >= 0 and N <= 100 and len(W) <= 50):
for row in N:
print(W)
return "Thank you for your time!"
try:
N = m.floor(int(input("Enter a number from 0 to 100: " )))
W = str(input("Enter a word: "))
except ValueError:
print("Invalid Input!")
print(print_word(N,W))
Answer:
#code (count_seq.py)
def count_seq():
n='2'
while True:
yield int(n)
next_value=''
while len(n)>0:
first=n[0]
count=0
while len(n)>0 and n[0]==first:
count+=1
n=n[1:]
next_value+='{}{}'.format(count,first)
n=next_value
if __name__ == '__main__':
gen=count_seq()
for i in range(10):
print(next(gen))
Explanation:
- Start with number 2. Use string instead of integers for easy manipulation
.
- Loop indefinitely
.
- Yield the integer value of current n
.
- Loop until n is an empty string
.
- Loop as long as n is non empty and first digit of n is same as first
.
- Append count and first digit to next_value
.