2 years ago

Find x to the nearest tenth.

Mathematics

1 answer:

Jlenok [28]2 years ago

6 0

Answer:

x = 11.3

Step-by-step explanation:

This is a right isosceles triangle

x² + x² = 16²

2x² = 256

x² = 128

x = 11.3

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2 years ago

Solve for 2x^2-4x+5=6

Softa [21]

To solve for a variable, you need to get it (x) by itself.

2x² - 4x + 5 = 6 Subtract 6 from both sides
2x² - 4x - 1 = 0 Plug this into the Quadratic Formula

a = 2 , b = -4 , c = -1
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x = $\frac{-(-4) \pm \sqrt{(-4)^2 - 4(2)(-1)} }{2(2)}$ Simplify
x = $\frac{4 \pm \sqrt{16 + 8} }{4}$ Simplify
x = $\frac{4 \pm 2\sqrt{6} }{4}$ Simplify by removing a 2 from every term
x = $\frac{2 \pm \sqrt{6} }{2}$ Simplify by taking the fraction apart
x = $\frac{2}{2} \pm \frac{ \sqrt{6} }{2}$ Change $\frac{2}{2}$ to 1
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