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belka [17]
3 years ago
7

While at School Brian had a math quiz every 6 days and a science quiz every four days. On February 15 he had both tests. Assumin

g no school days off when will he have both tests on the same day again.
Mathematics
1 answer:
kipiarov [429]3 years ago
4 0
March 3rd, assuming that it’s not a leap year and there are no school holidays.
Days x # of tests = days until both
6x2=12
4x3=12
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A school has 18 left-handed students. If 8% of the total number of students in the school are left-handed, what is the total num
LekaFEV [45]
The school has 225 students if 8% is left handed
7 0
3 years ago
Read 2 more answers
1/2 × 2 1/3 can u help
lawyer [7]
Thats easy its  7/6 hope this helps

7 0
3 years ago
Read 2 more answers
HELLPPP DUE TODAY AT 4
Natalka [10]

Answer:

2 and 2/3 for the first question

-1/8 for the second one

-1/5 for the third one

ive never done this type of question or maybe it was too long ago for me to remember but out of this answer choices i would guess that its the last one

this is 3

Step-by-step explanation:

you add the numerators which is the top number in order to get 2 and 2/3rds

you subtract 5 from 4 to get -1/8

same situation as the last one, subtract 15 from 11 to make it a negative 4/20 and then simplify that by dividing it by four to get 1/5th

this one i dont understand or remember how to do very well but if i had to guess its the last answer choice

this one you add 3/4 plus 1/4 in order to get 4/4 or rather 1, so basically its asking what 1+1+1 is which is 3

5 0
3 years ago
f the dean wanted to estimate the proportion of all students receiving financial aid to within 3% with 99% reliability, how many
Oksanka [162]

Answer:

n=1849

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Assuming that the proportion is estimated \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{2.58})^2}=1849  

And rounded up we have that n=1849

7 0
3 years ago
There are 8 books in a shelf that consist of 2 paperback books and 6 hardback books. If 4 books are selected at random without r
mixer [17]

Answer:D

Step-by-step explanation:

This is combination.

If 4 books selected out of eight book in the shelf:

(4 combination 8)= 70

For hardback selection:

Then selection of 4 books out of the hardback, it means there is no paperbach will be:

(4 combination 6)= 15

So , if at least one paperback selected will be : 70-15

That is 55

4 0
3 years ago
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