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allsm [11]
3 years ago
13

Without sketching the graph solve -6-x>10

Mathematics
2 answers:
kompoz [17]3 years ago
5 0

Answer:

x < -16

Step-by-step explanation:

-6-x>10

adding 6 in both sides:

-6-x+6 > 10+6

-x > 16

If you want to remove the negative sign from x, you'll have to change the inequality sign.

x < - 16

Hope this helps.

Shalnov [3]3 years ago
4 0

Answer:

x  <  - 16

Step-by-step explanation:

-6 - x > 10

group like terms

-x > 10 + 6

-x > 16

divide both sides by -1

-x/-1 < 16/-1

x < -16

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An automobile manufacturer who wishes to advertise that one of its models achieves 30 mpg (miles per gallon) decides to carry ou
Katyanochek1 [597]

Answer:

t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17  

p_v =P(t_{(5)}  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.  

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

Step-by-step explanation:

Data given and notation  

The mean and sample deviation can be calculated from the following formulas:

\bar X =\frac{\sum_{i=1}^n x_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)}{n-1}}

\bar X=29.35 represent the sample mean  

s=1.365 represent the sample standard deviation  

n=6 sample size  

\mu_o =30 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is lower than 30 or no, the system of hypothesis are :  

Null hypothesis:\mu \geq 30  

Alternative hypothesis:\mu < 30  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17  

P-value  

We need to calculate the degrees of freedom first given by:  

df=n-1=6-1=5  

Since is a one-side left tailed test the p value would given by:  

p_v =P(t_{(5)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.  

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

5 0
3 years ago
Choose the function table that matches the given rule<br> Rule:output=input -2
kirill [66]

Answer:

option B

Step-by-step explanation:

Rule:output=input -2

LEts analyze the table

we use the input and apply the rule to get the output

LEts subtract 2 from input to get the output

Input             Rule (input -2 )            Output

-3                         -3-2                          -5

-7                         -7-2                          -9

6                          6-2                            4

Option B matches with our table

   

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weqwewe [10]

Answer:

hi!!

Step-by-step explanation:

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konstantin123 [22]

Answer:

The answer is that he would have to work 6 hours to have enough money to buy the glove.

Step-by-step explanation:

1: Find the amount he needs to earn by subtracting $14 from $50: 50 - 14 = 36. So he needs to earn $36.00.

2: Since you have to find the amount of hours, you can divide $6 from $36 to get the amount of hours he needs to work: 36 / 6 = 6. Eamon only gets $6.00 per hour so he would have to work 6 hours to get the $36.00.

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vovikov84 [41]

Answer: D, neither A nor B

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3 0
2 years ago
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