Solving a system of equations, we will see that there are 6000 kg of coal on the pile.
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How many kilograms of coal are in the pile of coal?</h3>
Let's say that there are N kilograms of coal, and it is planned to burn it totally in D days, these are our variables.
We know that:
- If the factory burns 1500 kilograms per day, it will finish burning the coal one day ahead of planned.
- If it burns 1000 kilograms per day, it will take an additional day than planned.
Then we can write the system of equations:
(1500)*(D - 1) = N
(1000)*(D + 1) = N
Because N is already isolated in both sides, we can write this as:
(1500)*(D - 1) = N = (1000)*(D + 1)
Then we can solve for D:
(1500)*(D - 1) = (1000)*(D + 1)
1500*D - 1500 = 1000*D + 1000
500*D = 2500
D = 2500/500 = 5
Now that we know the value of D, we can find N by replacing it in one of the two equations:
(1500)*(D - 1) = N
(1500)*(5 - 1) = N
(1500)*4= N = 6000
This means that there are 6000 kilograms of coal on the pile.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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Answer:
x equals 3.00cm
Step-by-step explanation:
Use Pythagoras' Theorem.
a = (14x-45)
b = (16x+27)
c = (25x)
Plug in the variables above into Pythagoras' Theorem that is, a^2+b^2=c^2.
Solve the resulting quadratic equation and reject the negative answer as length is always positive.
1 1/6, 1 2/3, 1 5/6 is the order. :) hope I helped!
Hello,
y=k*(x-2)(x-4)
and is passing throught (3,1)
==>1=k*(3-2)(3-4)==>k=-1
y=-(x-2)(x-4) is an answer
Answer:
See explanation below.
Step-by-step explanation:
The scale factor can be found by dividing two corresponding side lengths. For instance, if you have two triangles, divide the new length of the larger or smaller triangle by the same side length of the original.
If the side length of the new was 9 and the old was 3 then the scale factor would be 9/3 = 3.
If it were flipped then the new would be 3 and the old would be 9. So the scale factor would be 3/9 = 1/3.
