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sammy [17]
3 years ago
14

What’s the standard form for 1,000,000+80,000+30+3

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
6 0
<h3>Answer:  1,080,033</h3>

=========================================

Explanation:

1,000,000 = 1 million

80,000 = 80 thousand

Adding those two would get us

1,000,000+80,000 = 1,080,000

Then we change those last two zeros at the end of "1,080,000" to 33 instead to get the final answer  1,080,033. This is done because we're adding 30+3 = 33 at the end.

----------------------

Extra info:

  • The number 1,080,033 is slightly over 1.08 million
  • 1,080,033 = 1 million, 80 thousand, 33
  • 1,080,033 = one million, eighty thousand, thirty-three
  • The use of commas between the words is optional. It's to give a sense of the pacing or pauses when reading out the number.
Alenkasestr [34]3 years ago
5 0

Answer:

1080033

Step-by-step explanation:

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Answer:

Only choices C and D are solutions

Step-by-step explanation:

6x + 3y = -15

y = -2x - 5

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6x - 6x - 15 = -15

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Since 0 = 0 is a true statement, both equations of this system are the same equation and represent a single line on the coordinate plane.

We need to check each choice in just one equation.

Let's use the second equation.

y = -2x - 5

A.

(2, 7)

7 = -2(2) - 5

7 = -4 - 5

7 = -9   False

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B.

(5, 0)

0 = -2(5) - 5

0 = -10 - 5

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C.

(-3, 1)

1 = -2(-3) - 5

1 = 6 - 5

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Solution

D.

-13 = -2(4) - 5

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Solution

Answer: Only choices C and D are solutions

7 0
3 years ago
What is 120000+129 and why answer correctly
Alex Ar [27]

Answer:

120,129

Step-by-step explanation:

7 0
4 years ago
Which expression represents the distance between point (0, a) and point (a, 0) on a coordinate grid?
o-na [289]

Answer:

\sqrt{2} a

Step-by-step explanation:

The distance between point (x1,y1) and (x2,y2) on a coordinate plane is given by expression \sqrt{(x1-x2)^2+(y1-y2)^2}

In the problem given coordinate points are

(0, a) and (a, 0).

Thus, distance between these points are given by

distance = \sqrt{(x1-x2)^2+(y1-y2)^2}\\=>distance = \sqrt{(0-a)^2+(a-0)^2}\\=>distance = \sqrt{(a)^2+(a)^2}\\\\=>distance = \sqrt{2a^2}\\=>distance = \sqrt{2} a

Thus , expression \sqrt{2} a gives the distance between point (0, a) and point (a, 0) on a coordinate grid.

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3 years ago
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3 years ago
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Answer:

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