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frez [133]
3 years ago
9

Solve b to the second power=77​

Mathematics
1 answer:
zubka84 [21]3 years ago
3 0

Answer:

\large\boxed{b=\pm\sqrt{77}}

Step-by-step explanation:

b^2=77\iff b=\pm\sqrt{77}\\\\\text{because}\\\\(-\sqrt{77})^2=77\ \text{and} \ (\sqrt{77})^2=77

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It takes 8,000 pounds of sand to make a beach volleyball court. If the organizers of a tournament purchase 24,000 pounds of sand
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Answer:

3 courts

Step-by-step explanation:

8,000 = 1 court

24,000 = x courts

8,000 x ? = 24,000

8,000 x <u>3</u> = 24,000

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Find the greatest common factor of the following monomials: 20a 46a^2 48a^6​
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2 years ago
I need help with 5 and 6
8_murik_8 [283]

Answer:

w = 6

RS = 13

Step-by-step explanation:

RS + ST = RT

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AC = AB + BC

56 = (x + 16) + (5x + 10)

56 = 6x + 26....then rearrange the equation to form...;

56 - 26 = 6x

30 = 6x...

where...; x = 5

AB = 5 + 16 and BC = 5(5) + 10

;AB = 21 ;BC = 35

7 0
3 years ago
Here's a graph of a linear function. Write the equation that describes that function. Express in slope-intercept form.
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10. The sum of the digits of a three-digit number is 11. If the digits are reversed, the new number is 46
Zarrin [17]

Answer:

hope this helps

Step-by-step explanation:

The sum of the digits of a three-digit number is 11.

If the digits are reversed, the new number is 46 more than five times the old number.

If the hundreds digit plus twice the tens digit is equal to the units digit, then what is the number?

:

Write an equation for each statement:

:

"The sum of the digits of a three-digit number is 11."

x + y + z = 11

:

The three digit number = 100x + 10y + z

The reversed number = 100z + 10y + x

:

" If the digits are reversed, the new number is 46 more than five times the old number."

100z + 10y + x = 5(100x + 10y + z) + 46

100z + 10y + x = 500x + 50y + 5z + 46

combine on the right

0 = 500x - x + 50y - 10y + 5z - 100z + 46

499x + 40y - 95z = -46

:

"the hundreds digit plus twice the tens digit is equal to the units digit,"

x + 2y = z

x + 2y - z = 0

:

Three equations, 3 unknowns

:

x + y + z = 11

x +2y - z = 0

-----------------Addition eliminates z

2x + 3y = 11

From the 2nd equation statement, we know that the 1st original digit has to be 1

2(1) + 3y = 11

3y = 11 - 2

3y = 9

y = 3 is the 2nd digit

then

1 + 3 + z = 11

z = 11 - 4

z = 7

:

137 is the original number

:

:

Check solution in the 2nd statement

If the digits are reversed, the new number is 46 more than five times the old number."

731 = 5(137) + 46

731 = 685 + 46

7 0
3 years ago
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