We can set up 2 equations given the information.
Let the price of advance ticket be represented by A and same day ticket by S
A + S = 50
20A + 40S = 1700
Solve for A in the first equation by subtracting S on both sides.
U will get A = 50 - S
Now substitute 50 - S for A in the second equation.
20 (50 - S) + 40S = 1700
1000 - 20S + 40S = 1700
20S = 700
S = 35
Same day ticket costs $35 and advance ticket costs $15
Answer: $11,600
Step-by-step explanation:
$2000 * 10% = $200
y = 200x + $2,000
12 * 4 = 48
48 = x
y = 200(48) + $2,000
y = $9,600 + $2,000
y = $11,600
Divide both sides by 5 to get t by itself, then you have your answer
Righ, so negative times positive=negative
negative+positive=positive
thereofr
positive>negative
factor -84 where the negative is smaller ex -12 and 13, not -14 and 10 so
-2 and 42 nope
fast forward
-6 and 14 yes
-6+14=8
so the numbers are -6 and 14
