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mariarad [96]
3 years ago
7

Plz explain question 37!

Mathematics
2 answers:
Gennadij [26K]3 years ago
5 0
I cant see the whole question
Flura [38]3 years ago
4 0
It’s 86 i just took something like this
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Multiply. (2x2 + 4x - 3)(x2 - 2x + 5)
BigorU [14]
For a moment, let y=x^2-2x+5. Then by the distributive property,

(2x^2+4x-3)p=2x^2p+4xp-3p


Again by the distributive property,

2x^2p=2x^2(x^2-2x+5)=2x^4-4x^3+10x^2

4xp=4x(x^2-2x+5)=4x^3-8x^2+20x

-3p=-3(x^2-2x+5)=-3x^2+6x-15

Taking everything together, we get

(2x^2+4x-3)(x^2-2x+5)=(2x^4-4x^3+10x^2)+(4x^3-8x^2+20x)+(-3x^2+6x-15)
(2x^2+4x-3)(x^2-2x+5)=2x^4-x^2+26x-15
7 0
3 years ago
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Find the equation of the line that passes through the following points. Write the equation in slope-intercept form.
ra1l [238]

Answer:

The equation in the slope-intercept form will be:

y  = 1/4x - 7

Step-by-step explanation:

Given the points

  • (-4.-8)
  • (-8, -9)

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}

\left(x_1,\:y_1\right)=\left(-4,\:-8\right),\:\left(x_2,\:y_2\right)=\left(-8,\:-9\right)

m=\frac{-9-\left(-8\right)}{-8-\left(-4\right)}

m=\frac{1}{4}

We know that the slope-intercept of line equation is

y=mx+b

where m is the slope and b is the y-intercept

substituting m = 1/4 and the point (-4, -8) to find the y-intercept 'b'

y = mx+b

-8 = 1/4(-4)+b

-8 = -1 + b

b = -8+1

b = -7

so the y-intercept = b = -7

substituting m = 1/4 and b = -7 in the slope-intercept form of line equation

y = mx+b

y  = 1/4x + (-7)

y  = 1/4x - 7

Thus, the the equation in slope-intercept form will be:

y  = 1/4x - 7

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Are there always the same number of prime numbers between 2 consecutive multiples of 10? Explain.
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