A = P(1 + rt)
Where:
<span>·
</span>A = Total Accrued Amount (principal + interest)
<span>·
</span>P = Principal Amount
<span>·
</span>I = Interest Amount
<span>·
</span>r = Rate of Interest per year in decimal; r = R/100
<span>·
</span>R = Rate of Interest per year as a percent; R = r * 100
<span>·
</span>t = Time Period involved in months or years
A = 15,000(1+ 0.07(5))
A = 20,250 they acquired in total for 5 years
The yearly amount the get is 15,000 xx 0.07 = $ 1050 per
year
So in the next 25 years addition of 1050x25 = $26250 they
will get
Answer:
BD does bisect the angle created by ABC, however it does not bisect segment AC. So it really depends on what you are determining the bisection to be.
Step-by-step explanation:
We can tell that it is bisecting the angle since it creates two congruent angles.
We can tell that it does not bisect the segment as AD and CD are not the same length.
Answer:
I should use at least 304 students
Step-by-step explanation:
Margin error (E) = t × sd/√n
E = 40
sd = 300
confidence level (C) = 98% = 0.98
significance level = 1 - C = 1 - 0.98 = 0.02 = 2%
t-value corresponding to 2% significance level and infinity degree of freedom is 2.326
n = (t×sd/E)^2 = (2.326×300/40)^2 = 17.445^2 = 304 (to the nearest integer)
Answer:
(x-1)²+ (y-0.5)²=6.25
Step-by-step explanation:
<u>The standard form of equation of a circle is;</u>
(x-a)²+(y-b)²=r² where (a,b) are the center of the circle and r is the radius
<u>Finding the mid-point of the given points</u>
(-1,2) and (3,-1)⇒midpoint will be 1/2(x₁+x₂) , 1/2(y₁+y₂)
midpoint= {1/2(-1+3), 1/2(2+-1)}
midpoint=(1,0.5)
<u>Finding the radius r; the distance from the center to either of the given two points</u>
Apply the distance formula d=√ (x₂-x₁)² +(y₂-y₁)²
Taking (x₁,y₁) as (1,0.5) and (x₂,y₂) as (-1,2) then
d=√ (-1-1)² +(2-0.5)²
d= √ (-2)²+(1.5)²
d=√4+2.25⇒√6.25⇒2.5
r=2.5
<u>Equation of the circle</u>
(x-1)² + (y-0.5)²=2.5²
(x-1)²+ (y-0.5)²=6.25
The greatest area he can fence is 64 ft².
In order to maximize area and minimize perimeter, we use dimensions that are as close to equivalent as possible. 32 feet of fence for 4 sides gives us 8 feet of fence per side. We would have a square whose side length is 8; the area would be 8*8 = 64.
